Write the equation of a secant line? Screenshot of the question is attached
1 answer:
Answer:
y = 12x - 13
Step-by-step explanation:
The two points you want the line through are ...
... (-4, h(-4)) = (-4, -61)
and
... (2, h(2)) = (2, 11)
The 2-point form of the equation of a line is applicable. For (x1, y1) and (x2, y2), the equation is
... y = (y2-y1)/(x2-x1)·(x-x1) +y1
... y = (-61-11)/(-4-2)·(x -2) + 11 . . . . putting in the point values
... y = 12(x -2) + 11 . . . . . . . . . . . . . simplify
... y = 12x -13 . . . . . . . . . . . . . . . . . eliminate parentheses, collect terms
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