3 years ago

How to solve x^2-4x-5=0 by using the quadratic formula?

Mathematics

1 answer:

padilas [110]3 years ago

3 0

Answer:

x = 5 or -1, put numbers into the formula and calculate

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Divide (x^3-20x+16)/(x-4)

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$\frac{( x^{3}-20x+16) }{(x-4)}$

Use the rational root theorem:
$a_{o}$ =16, $a_{n}$ =1

The dividers of $a_{o}$ : 1,2,4,8,16
The dividers of $a_{n}$ : 1

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4 years ago

Twenty more than four times a number is equal to the difference between 139 and three times the number. Find the number.

Lady_Fox [76]

Answer:

x = 17

Step-by-step explanation:

First, let's turn this into an equation:

twenty more ( +20 ) than four times a number ( 4x ) is equal ( = ) to the difference ( - ) between 139 and 3 times the number ( 3x ).

4x + 20 = 139 - 3x

Now let's solve:

Subtract 20 from each side:

4x = 119 - 3x

Add 3x to each side:

7x = 119

Divide each side by 7:

x = 17

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