Well you have to remember to find the slope you have to use Y2-Y1 over X2-X1 so your answer will be -14 over 1
Let length = l
width = w
length = 3 times width = 3w
Area of the land = 75 sq. m
Area = length × width = 3w×w = 75
3w²=75
w²=25
w=5 m
length = 3×15 = 15m
Now lets make the figure with the path of width x meters
(Refer the attached figure for easy understanding)
The inner length is the length of the rectangle reduced by x meters on either side due to the path
that is 15-x-x = 15-2x
the inner width is the width reduced by x meters in either side
= 5-x-x = 5-2x
Now lets calculate the inner area = inner length × inner width
(15-2x)×(5-2x)
= 
=
sq. m
Now the function to calculate the cost
f(x) is given by $3.00 × area of the inner land
f(x) = 3 × {75-40x+4x²)
= 225-120x+12x²
or
= 12x²-120x+225
Answer:
Step-by-step explanation:
Slope of HI = slope of DE
= (24-32)/(12-8)
= (-8)/4
= -2
Well the shortest length would be 16 because you would have to divide 80 by 5, so it would be greater than or equal to 16. Is that the whole question or is there more to it?