Answer:
Neither
Step-by-step explanation:
First, you need to put your equations in y=mx+b form
Your first equation...
5x + 4y = 3
4y = 3-5x
y = -5/4x + 3/4
Your second equation...
5x-4y = -3
-4y = -5x -3
y = 5/4x + 3/4
The slopes aren't the same and are not reciprocals, so the answer would be neither.
Answer:
4) in question it should be triangleMNP and NOP
reason by SSS axiom
5) reason is as the angles of congurent triangles are equal)
Answer:
3
Step-by-step explanation:
parts planted with strawberries is
1/2 of 6 parts = 3 parts
remaining parts have watermelon planted
6- 3 =3 parts
The problem statement tells us that
- AM ≅ MB, ∴ ΔAMB is isosceles
- AM ≅ MC, ∴ ΔAMC is isosceles
Base angles of an isosceles triangle are equal, so ∠MAB ≅ ∠MBA. ∠AMC is the exterior angle opposite those two, so it is equal to their sum, 2∠MAB.
The base angles in isosceles ΔAMC are equal to half the difference between the apex angle, ∠AMC, and 180°. That is,
... ∠MAC = (1/2)(180° -∠AMC) = (1/2)(180° -2∠MAB) = 90° -∠MAB
The angle at A of ΔABC is the sum of the two angles created by the median AM. That is ...
∠A = ∠MAC + ∠MAB
∠A = (90° -∠MAB) +∠MAB
∠A = 90°
_____
Maybe a shorter way to get there is to realize that ...
... MA ≅ MB ≅ MC
so M is the center of a circle with BC as a diameter and A a point on the circle. Angle BAC is inscribed in the semicircle and subtends an arc of 180°, so angle A is 90°.
