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e-lub [12.9K]
2 years ago
9

An example of a number that is a rational number but not whole

Mathematics
1 answer:
Charra [1.4K]2 years ago
8 0

Answer:

2/3

Step-by-step explanation:

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The sum of two consecutive odd intergers is 92
frutty [35]

Answer:

45,47

Step-by-step explanation:

(x)+(x+2)=92

= 2x+2=92

=2x=90

x=45

x+2=47

8 0
3 years ago
Read 2 more answers
For a horizontal demand curve
kkurt [141]

Answer:

d. both the slope and price elasticity of demand are equal to 0.

Step-by-step explanation:

In order to graph the demand curve, the quantity demanded is plotted along x-axis and the price is plotted along y-axis. An image attached below shows the horizontal demand curve.

Horizontal demand curve, as its name indicates, is a horizontal line which is parallel to x-axis. Since, the slope of any line parallel to x-axis is 0, we can conclude that the slope of Horizontal demand curve is 0.

A horizontal demand curve can be observed for a perfectly competitive market. Since, its a perfect competition, the price of a product by all competitors will be the same. In this case, if a firm decides to increase the price, he will loose his market share as no customer will buy the product at increased price. They will rather go with the other competitor who is offering a similar product at lower price.

On the other hand, if a competitor decides to lower his price in such case, he will experience loss. Therefore, the competitors do not have the option to change the price. Therefore, we can say the price elasticity of demand in this case is 0.

So, option D describes the horizontal demand curve correctly.

3 0
2 years ago
PLEASE HELP ASAP<br><br> 3/10/p=4/5/1/4
kati45 [8]

Answer:

3

1

0

=

4

5

1

4

Step-by-step explanation:

6 0
2 years ago
To find the interquartile range you need to ____the upper and lower quartile values.​
Blababa [14]

Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

8 0
3 years ago
Read 2 more answers
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
2 years ago
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