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lukranit [14]
3 years ago
13

MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!1

Mathematics
1 answer:
Reil [10]3 years ago
4 0

4(50) +3r = 365

200+3r = 365

3r =165

r = 165/3

r = 55

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The diagonals of a kite are 21cm and 11cm. Find the perimeter of the kite.
WITCHER [35]

Answer:

Perimeter: 64 cm

Step-by-step explanation:

21 + 21 = 42 cm 11 + 11 = 22 cm

42 + 22 = 64 cm

6 0
3 years ago
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Heeelllppp me please :)
Sophie [7]
The common ratio is 3.

I hope this helps!
4 0
3 years ago
Zahra has paper rectangles of different sizes. Every rectangle is 5 centimeters longer than it is wide. Is there a proportional
Alika [10]

Answer: The answer is NO. Explained below.


Step-by-step explanation:  Given that Zahra has a number of rectangles of different sizes which are made of paper. Also, the length of every rectangle is 5 cm more than its breadth.

We are to find whether the relationship between lengths and breadths of rectangles is proportional or not.

Let,  'l' represents the length and 'b' represents the breadth of any of these rectangles, then according to the given information, we can write

l = b + 5.

For a proportional relationship, we need a relation of the form

l = k × b, which is not always possible in the given case.

For example, if l = 8, b = 3, and l=9, b=4 then we cannot write

l = k × b, for a constant k.

Hence there is no proportional relationship  between the lengths and widths of these rectangles.

Thus, the answer is NO. Hence explained.


5 0
3 years ago
Read 2 more answers
Step by step explanation please so I can see how to do it
Basile [38]

Answer:

875 units

Step-by-step explanation:

35/5=7 AD and BC =7

25/5=5 the ratio of the to rect are 5

7(5)=35 EH and FG =35

25(35)=875

can you mark me the brainliest please

3 0
3 years ago
Reimann Sum... I got it wrong twice... Please help and provide step by step clear explaination. I'd appreciate it.
AnnyKZ [126]
Formula for Riemann Sum is:
\frac{b-a}{n} \sum_{i=1}^n f(a + i \frac{b-a}{n})
interval is [1,3] so a = 1, b = 3
f(x) = 3x , sub into Riemann sum

\frac{2}{n} \sum_{i=1}^n 3(1 + \frac{2i}{n})

Continue by simplifying using properties of summations.
= \frac{2}{n}\sum_{i=1}^n 3 +  \frac{2}{n}\sum_{i=1}^n \frac{6i}{n} \\  \\ = \frac{6}{n}\sum_{i=1}^n 1 +  \frac{12}{n^2}\sum_{i=1}^n i \\  \\ =\frac{6}{n} (n) + \frac{12}{n^2}(\frac{n(n+1)}{2}) \\  \\ =6+\frac{6}{n}(n+1) \\  \\ =12 + \frac{6}{n}

Now you have an expression for the summation in terms of 'n'.

Next, take the limit as n-> infinity.
The limit of \frac{6}{n} goes to 0, therefore the limit of the summation is 12.

The area under the curve from [1,3] is equal to limit of summation which is 12.
7 0
3 years ago
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