<u>Answer-</u>
<em>The length of line segment WU is</em><em> 4 cm</em><em>.</em>
Option 1. 4 cm is correct.
<u>Solution-</u>
As given that, RSTU is an parallelogram.
RT and SU are its two diagonals. They intersect each other at point W.
Properties of parallelogram is that they bisect each other.
i.e SW = WU and RW = WT
As given that, SW = 4 cm.
So, WU = SW = 4 cm
Therefore, the length of line segment WU is 4 cm.
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
Answer:
B. $54
Step-by-step explanation:
PEMDAS: Do multiplication and division first
65 - (2*7=14) + (9/3=3)
65-14+3
Go from left to right and solve
51+3=54
Answer: X= 16
Step-by-step explanation:
