Question

Jason had three more than four times the amount of money that Jeff has. Together they have $72. How much money does each person have?

Answer 1

Answer:

Jason has $58.20 and Jeff has $13.80.

Step-by-step explanation:

Let x represent the amount of money Jason has, and y represent the amount of money Jeff has.

We know that together they have $72. So, we can write the following equation:

$x+y=72$

We know that Jason has three more than four times the amount of money Jeff has. So:

$x=3+4y$

This is a system of equations. We can solve it by using substitution. Let's substitute the second equation into the first. This yields:

$(3+4y)+y=72$

Combine like terms:

$5y+3=72$

Subtract 3 from both sides:

$5y=69$

Divide both sides by 5:

$y=69/5=\ 13.80$

So, Jeff has $13.80

We know that Jason has three more than four times the amount of money Jeff has.

Therefore, Jason has:

$x=13.8(4)+3$

Multiply and add:

$x=\ 58.20$

So, Jason has $58.20 and Jeff has $13.80.

And we're done!