Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:

Step-by-step explanation:
Given

Required
Approximate to the nearest ten thousand
First, identify the digit at the ten thousand position
From the given numbers of visitors, the digit is 2.
So, the next digit (which is 7) will be approximated and added to 2.
7 > 5. So, 1 will be added to 2.
The number of visitors becomes:

Answer:
The specific gravity of kerosene is 0.82
Step-by-step explanation:
Let
x -----> the weight in grams of a cubic centimeter of Kerosene
y ----> the weight in grams of a cubic centimeter of water
z ---> the specific gravity of a substance
so

we have

substitute the values

Answer:
x = 1.5
Step-by-step explanation:
Given


Required
Find the value of x.
First, the inequalities need to be rewritten and merged;
if
, then

Multiply both sides by 2


Similarly;

Multiply both sides by 2


Merging these results together; to give

This means that the range of values of x is from 1.5 to 4.9999....
From the question, x is the smallest rational number; from the range above (
), the minimum value of x is 1.5 and 1.5 is a rational number;
Hence, x = 1.5
(6÷2)+(5+2×3)=24
I got this so this is the answer
;D