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3 years ago

No rush. I need help on this question. I need an explanation pleaseeeeee. Thank you in advance!

Mathematics

2 answers:

maksim [4K]3 years ago

8 0

Answer:

2 vans and 7 busses

Step-by-step explanation:

Let x=# of busses

Let y=# of vans

55x+12y=409

x=y+5

55(y+5)+12y=409

55y+275+12y=409

67y+275=409

134=67y

y=2

There were two vans, and y+5 (7) busses

Alina [70]3 years ago

6 0

Answer:

1) 275

2)60

Step-by-step explanation:

1) 55 x 5 =275

2) 12 x 5 = 60

Hope it helps!

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Destiny can run one-eighth of a mile in three-quarters of a minute, and she can walk one-quarter of a mile in 4 minutes. How man

yarga [219]

Answer:

a) Destiny can run 1 mile is 6 minutes.

b) Destiny can walk back 1 mile is 16 minutes.

Step-by-step explanation:

The running rate of Destiny is

$(\frac{1}{8}) \textrm{mile in} (\frac{3}{4}) \textrm{minutes}$

So, she runs 1 mile in $8 \times (\frac{3}{4} )\textrm{minutes}$

= 6 minutes

Hence, Destiny can run 1 mile is 6 minutes.

The walking rate of Destiny is

$(\frac{1}{4}) \textrm{mile in} 4 \textrm{minutes}$

So, she walks 1 mile in $4 \times (4 )\textrm{minutes}$

= 16 minutes

Hence, Destiny can walk back 1 mile is 16 minutes.

4 0

3 years ago

A Square has the vertices at (-2,6) (6,1) (1,-7) (-7,-2). At what point do the diagonals of the square intercect

DerKrebs [107]

Answer: At point ( $-\frac{1}{2},-\frac{1}{2}$ )

Step-by-step explanation: Diagonal is a line uniting two opposite points. In a square, the diagonals intersect in a 90° and bisect each other, i.e., divides each diagonal into two segments of the same length.

In other words, the diagonals of a square meet at their midpoint, which is found as the following:

(x,y) = $(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2})$

The opposite vertices of the given square are (-2,6) and (1,-7).

So, the intersection is

(x,y) = $(\frac{-2+1}{2} ,\frac{6-7}{2})$

(x,y) = $(-\frac{1}{2},-\frac{1}{2} )$

The diagonals of square with vertices (-2,6)(6,1)(1,-7)(-7,-2) intersect at point $(-\frac{1}{2},-\frac{1}{2} )$ .

4 0

3 years ago

Algebra 1 3c-d=t solve for d

Oduvanchick [21]

First you need to get d alone. so subtract 13c from t and then flip the signs to make d positive so 13c-t=d

4 0

3 years ago

What is the solution for this inequality? -4x ≤ 28 A. x ≥ -7 B. x ≤ 7 C. x ≤ -7 D. x ≥ 7

svetoff [14.1K]

Answer:

$\boxed{Option A }$

Step-by-step explanation:

=> $-4x \leq 28$

Dividing both sides by -4

=> $x \geq 28/-4$

=> $x \geq -7$

3 0

4 years ago

HELP ME!!

mihalych1998 [28]

Answer:

cos2∅= -0.557

tan2∅= --1.49

Step-by-step explanation:

Given:

cos∅=-8/17

By trigonometric ratios:

as cos∅=adjacent/hypotenuse

hypotenuse= 17

adjacent=-8

Now finding perpendicular using Pythagoras theorem:

c2=a2+b2

17^2=(-8)^2+b^2

289-64=b^2

b^2=225

b=±15

b=-15 as ∅ is in third quadrant so both the opposite and adjacent sides be in 3rd quadrant

tan∅=opposite/adjacent

tan∅=-15/-8

sin∅=-15/17

Now finding cos2∅

cos2∅= 1-2sin^2∅

=1 - 2(-15/17)^2

=1 -450/289

= -161/289

=-0.557

finding tan2∅

tan2∅= 2tan∅/1-tan^2∅

= 2(-15/-8) / 1-(-15/-8)^2

= (15/4) / 1-225/64

=(15/4) / (-161/64)

= -240/161

=-1.49 !

6 0

3 years ago