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Nikitich [7]
3 years ago
10

Jim earns $1,600 per month after taxes. He is working on his budget and has the first three categories finished.

Mathematics
2 answers:
Julli [10]3 years ago
8 0
He wont have a problem he still has $432 left
soldi70 [24.7K]3 years ago
7 0

B.

He has used the highest recommended percentages to calculate the amounts for the three categories.

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Why is the inequality x≤6 equivalent to the inequality x−5≤6−5
Monica [59]

Two inequalities are equivalent if they have the same set of solutions.

x - 5 ≤ 6 - 5

x - 5 ≤ 1    |add 5 to both sides

x ≤ 6

8 0
3 years ago
Find the measure of the red arc or chord in ⊙C. The measure of arc XYZ is a °
Igoryamba

The points on the red arc are points A and B

The measure of the red arc is 75 degrees

<h3>How to determine the measure of arc XYZ?</h3>

From the complete question, we have:

Angle DCE = 75 degrees

By vertical angles theorem,

Angle ACB = Angle DCE = 75 degrees

So, we have:

Angle ACB = 75 degrees

The measure of the red arc is the same as the measure of the angle ACB.

So, we have:

Red arc = 75 degrees

Hence, the measure of the red arc is 75 degrees

Read more about arc and chords at:

brainly.com/question/25871159

3 0
2 years ago
Help mememememme please ☹️
Dmitriy789 [7]

An exterior angle is formed by one side of the triangle, and a side EXTENDED outside the triangle. Two angles are like that, ∠4 and ∠2.


Angle 3 is NOT an exterior angle because it is made up of two extended sides. It does not use one of the sides of the triangle.

3 0
3 years ago
The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Artemon [7]

Answer:

P(X \geq 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N(\mu=73,\sigma^{2}=3^{2})

The z score probability distribution is given by;

           Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 73

           \sigma = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X \geq 74)

 P(X \geq 74) = P( \frac{X-\mu}{\sigma} \geq \frac{74-73}{3} ) = P(Z \geq 0.33) = 1 - P(Z < 0.33)

                                               =  1 - 0.62930 = 0.3707                  

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

3 0
3 years ago
Answer C and D please
DENIUS [597]

Answer:

C. solution:

3(3c-2) = 5(2c-1)

or, 9c-6 = 10c-5

or, -6+5 =<em> </em>10c-9c

or, -1 = 1c

Hence, c = -1.

D. solution:

5(5-2a) = 4(6-a)

or, 25-10a = 24 - 4a

or, 25-24 = -4a+10a

or, 1 = 6a

or, 1/6 = a

Hence, a = 1/6.

6 0
3 years ago
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