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4 years ago

If f(x) =- 3x - 9, find f(5)

Mathematics

1 answer:

lidiya [134]4 years ago

3 0

Answer:

f(5) = - 24

Step-by-step explanation:

To evaluate f(5), substitute x = 5 into f(x) , that is

f(5) = - 3(5) - 9 = - 15 - 9 = - 24

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A town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Aven

spin [16.1K]

Answer: Option B -- 72°

Step-by-step explanation:

If a town planner wants to build two new streets, Elm Street and Garden Road, to connect parallel streets Maple Drive and Pine Avenue. Using Trapezoid E F G H is shown. F G is Maple Drive, G H is Garden road, E H is Pine avenue, and E F is Elm Street. Sides F G and E H are parallel. Angle G is 108 degrees. In trapezoid EFGH, EF ≅ HG. The measure of the angle between Elm Street and Pine Avenue is 72°

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3 years ago

GEOMETRY Find the volume of the figure

GenaCL600 [577]

V = 3.14(11)^2(10)
379.94 (10)
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3 years ago

Cant seem to figure out the total surface area

ki77a [65]

Answer:

189

Equation for surface area is 2bs +b squared ( b is base and a is side)

Step-by-step explanation:

2bs+b squared

2 * 7 * 10=140

B squared = 7 squared which is 49

140 + 49=189.

Hope it helped.

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3 years ago

25 ÷ (x + 2) = 5 is an equation or expression

mario62 [17]

The answer is an expression because you can not solve for x.

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3 years ago

A ball is thrown straight up from the top of a 40 feet tall building with an initial speed of 24 feet per second. The height of

rjkz [21]

Answer:

1)The ball hits the ground after 3 seconds.

2)The maximum height of the ball is 49 feet

3)It takes 1.25 seconds to reach its maximum height

Step-by-step explanation:

Height of building = 40 feet

We are given that A ball is thrown straight up from the top of building with an initial speed of 24 feet per second.

So, The height of the ball as a function of time can be modeled by: $h(t)=-16t^2+40t+24$

1)After how many seconds the ball hit the ground.

Substitute h(t)=0

So, $-16t^2+40t+24=0\\-2t^2+5t+3=0\\2t^2-5t-3=0\\2t^2-6t+t-3=0\\2t(t-3)+1(t-3)=0\\(2t+1)(t-3)=0\\t=\frac{-1}{2} , 3$

Since time cannot be negative

So,the ball hits the ground after 3 seconds.

2)What is the maximum height of the ball?

It takes maximum height at vertex

Formula : $t = \frac{-b}{2a}$

$t=\frac{-40}{2(-16)}=1.25 seconds$

Substitute the value of t in function

$h(1.25)=-16(1.25)^2+40(1.25)+24\\h(1.25)=49 feet$

So,the maximum height of the ball is 49 feet

3).How long did it take for the ball to reach its maximum height?

It takes 1.25 seconds to reach its maximum height

6 0

4 years ago

If f(x) =- 3x - 9, find f(5)​

If f(x) =- 3x - 9, find f(5)