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Genrish500 [490]
3 years ago
10

Which angle measure below is not a possible measure of an exterior angle of a regular polygon?

Mathematics
1 answer:
geniusboy [140]3 years ago
7 0
The angle measure that would not be applicable as an interior angle of a polygon would 54 degrees. It is because the angle measure when divided by the maximum sum of an interior angle of 360 degrees, would not yield a whole number. The largest measure of an angle inside a polygon should be 120 degrees.
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if u can answer all them correctly ill make a post for u and u can have all my coins just pls answer them all im begging
Shkiper50 [21]

Answer: this is a continuation starting in number 4 (use the same steps as example 3)

Step-by-step explanation:

-12

45

-12

14

32

-2

5

7 0
3 years ago
The four partners in a business decide to split the profits of their company in the ratio 2 : 3 : 3 : 5 .
Snowcat [4.5K]

Answer:

$10,000

Step-by-step explanation:

the profit was divided to 2+3+3+5=13 parts

the largest amount of profit

=$26,000×5/13

=$10,000

5 0
3 years ago
Out of students appeared in an examination 75% passed in English, 55%. passed in Mathematics, 5% failed in both subjects and 21
rusak2 [61]

Based on the percentage that passed English and those who passed Mathematics and those who failed and passed both, the total number of students who appeared in the examination are 60 students.

The number of students who passed only in Math are 12 students.

<h3>What number of students sat in the exam?</h3>

This can be found as:

= Total who passed English only + Total who passed Math only + Total who failed both + Total who passed both

Assuming the total is n, the equation becomes:

n = 0.75n - 21 + 0.55n - 21 + 21 + 0.05n

n = 1.35n - 21

21 = 0.35n

n = 21 / 0.35

= 60 students

The number who passed mathematics only is:

= (60 x 55%) - students who passed both

= 33 - 21

= 12 students

Find out more on Venn diagrams at brainly.com/question/24581814

#SPJ1

4 0
1 year ago
PLEASEEE HELP MEEEE<br><br>NO LINKSSS
Artemon [7]

Answer:

\huge\boxed{(2,\ 3);\ (-1,\ 6)}

Step-by-step explanation:

f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right

substitute (1) to (2):

x^2-2x+3=-x+5     add x to both sides

x^2-2x+x+3=-x+x+5

x^2-x+3=5        subtract 5 from both sides

x^2-x+3-5=5-5

x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}

substitute the values of x to (2):

x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}

3 0
2 years ago
Create a set of five lengths so that:
lozanna [386]

Answer:

1, 2, 3, 7, 10

Step-by-step explanation:

5 0
2 years ago
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