Answer:
0.84882
Step-by-step explanation:
Given:-
The production process is in control is number of chocolate chips in a cookie. The mean number of chocolate chips per cookie is 6.0.
λ = 6.0
- We define a random variable (X) that denotes the number of chocolate chips inspected on a cookie follows a poisson distribution:
X ~ Po ( 6.0 )
Find:-
how many cookies should the manager expect to discard from the batch if the policy is that each cook must have at least four chocolate chips?
Solution:-
- We will use the probability mass function of Poisson variate (X). Given:

Where, k = 0 , 1 , 2 , 3 , 4 , 5 , 6 , .... , n = 100
- The required probability is P ( X ≥ 4 ); Using the pmf function we have:
![P ( X \geq 4 ) = 1 - P ( X < 4 )\\\\P ( X \geq 4 ) = 1 - [ \frac{6^0*e^-^6}{0!} + \frac{6^1*e^-^6}{1!} + \frac{6^2*e^-^6}{2!} + \frac{6^3*e^-^6}{3!} ]\\\\P ( X \geq 4 ) = 1 - [ 0.00247 + 0.01487 + 0.04461 + 0.08923 ]\\\\P ( X \geq 4 ) = 1 - [ 0.15118 ] = 0.84882](https://tex.z-dn.net/?f=P%20%28%20X%20%5Cgeq%20%204%20%29%20%3D%201%20-%20P%20%28%20X%20%3C%204%20%29%5C%5C%5C%5CP%20%28%20X%20%5Cgeq%20%204%20%29%20%3D%201%20-%20%5B%20%5Cfrac%7B6%5E0%2Ae%5E-%5E6%7D%7B0%21%7D%20%2B%20%5Cfrac%7B6%5E1%2Ae%5E-%5E6%7D%7B1%21%7D%20%2B%20%5Cfrac%7B6%5E2%2Ae%5E-%5E6%7D%7B2%21%7D%20%20%2B%20%5Cfrac%7B6%5E3%2Ae%5E-%5E6%7D%7B3%21%7D%20%5D%5C%5C%5C%5CP%20%28%20X%20%5Cgeq%20%204%20%29%20%3D%201%20-%20%5B%200.00247%20%2B%200.01487%20%2B%200.04461%20%2B%200.08923%20%5D%5C%5C%5C%5CP%20%28%20X%20%5Cgeq%20%204%20%29%20%3D%201%20-%20%5B%200.15118%20%5D%20%3D%200.84882)