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Daniel [21]
3 years ago
5

In a certain school,260 students were present on monday,270 on tuesday,280 on wednesday,and 250 on thursday find the average num

ber of students present on those four days
Mathematics
1 answer:
Lunna [17]3 years ago
6 0

Answer:

The average number of students present are 265

Step-by-step explanation:

Given the number of students present on monday were 260, the number of students present on tuesday were 270 , the number of students present on wednesday were 280 , the number of students present on thursday are 250.

Now the numbers are 260, 270, 280, 250

We should basically find the average of these four observations

We know that the Average=\frac{sum of the observations}{number of observations}

sum of the observations is 260+270+280+250=1060

number of observations are 4

Average=  \frac{1060}{4}   =265

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Alenkasestr [34]
The answer is C as the numbers for y increase greatly when the number of x increase
4 0
2 years ago
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The top of a 15-foot ladder leans against a wall, and the bottom of the ladder slides away from the wall at a rate of 4 ft/sec.
Andrej [43]
The ladder, the ground and the wall form a right triangle; the ladder length (L) is the longest side of this triangle.  L^2 = h^2 + x^2, where h represents the height of the point on the wall where the ladder touches the wall, and x represents the distance of the base of the ladder from the wall.

We need dh/dt, which will be negative because the top of the ladder is sliding down the wall.

Starting with h^2 + x^2 = L^2, we differentiate (and subst. known values such as x = 5 feet and 4 ft/sec to find dh/dt.  Note that since the ladder length does not change, dL/dt = 0.  This leaves us with

      dh          dx
2h ---- + 2x ----- = 0.
       dt           dt

Since x^2 + h^2 = 15^2 = 225,          h^2 = 225 - (5 ft)^2 = 200, or
200 ft^2 = h^2.  Then h = + sqrt(200 ft^2) 

Substituting this into the differential equation, above:

2[sqrt(200)] (dh/dt) + 2 (5) (4 ft/sec) = 0.  Solve this for the desired quantity, dh/dt:

[sqrt(200)] (dh/dt) + (5)(4) = 0, or

                   dh/dt = -20 / sqrt(200) = (-1.41 ft / sec)   (answer)

This result is negative because the top of the ladder is moving downward.


4 0
3 years ago
The average radius of Jupiter is 4.34 x 10^4 miles. The average sun radius of the sun is 4.32 x 10^5. How many times greater is
Oksanka [162]

Answer:

The average radius of sun is approximately 9.95 times the average radius of Jupiter.                                

Step-by-step explanation:

We are given the following in the question:

Average radius of Jupiter =

4.34\times 10^{4}\text{ miles}

Average radius of the sun =

4.32\times 10^{5}

Relation between average radius of sun and average radius of Jupiter =

\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}}\\\\= \frac{4.32\times 10^{5}}{4.34\times 10^{4}}\\\\\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}} = 9.953917\\\\\text{Average radius of Sun} \approx 9.95\times \text{(Average radius of Jupiter)}

Thus, the average radius of sun is approximately 9.95 times the average radius of Jupiter.

7 0
3 years ago
Porqué el valor del coeficiente de la variable al cuadrado de una función cuadratica no puede ser cero?
Nady [450]

Answer:

Ver respuesta abajo

Step-by-step explanation:

Una ecuación cuadrática es una ecuación que tiene la siguiente forma:

ax² + bx + c = 0

Donde:

a, b y c: coeficientes numéricos que acompañan a la incógnita.

Ahora bien, una función cuadrática es basicamente la misma ecuación cuadrática pero representada graficamente en un plano cartesiano.

Para que una ecuación o función sea cuadrática es absolutamente necesario y obligatorio que su expresión en forma de ecuación tenga el elemento "ax²", pues el "cuadrado" que es el exponente 2 que eleva la incógnita es lo que le da la característica de ecuación o función cuadrática.

Si el coeficiente que acompaña al x², es decir, el valor de a es cero, automaticamente pierde la condición de ser una función o ecuación cuadrática pues dicho término se hace cero su valor. En otras palabras, si x es un número cualquiera y está representado como incógnita, ¿qué sucede cuando multiplicas cualquier número por cero?, en este caso, el resultado es igual a cero:

Ejemplo:

0x² = 0 * x² = 0.

Por tanto, si el término cuadrático se hace cero, ya pierde la condición de cuadraticidad, y su gráfico no sería de forma parabólica, solo quedaría los términos bx + c, pero eso ya pertenece a una ecuación lineal o función afín.

Espero esto te sirva.

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2 years ago
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