In a certain school,260 students were present on monday,270 on tuesday,280 on wednesday,and 250 on thursday find the average num
1 answer:
Answer:
The average number of students present are 265
Step-by-step explanation:
Given the number of students present on monday were 260, the number of students present on tuesday were 270 , the number of students present on wednesday were 280 , the number of students present on thursday are 250.
Now the numbers are 260, 270, 280, 250
We should basically find the average of these four observations
We know that the
sum of the observations is 260+270+280+250=1060
number of observations are 4
Average= =265
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Answer:
Step-by-step explanation:
<em><u>Given</u></em><u>:</u> A line m is perpendicular to the angle bisector of ∠A. We call this
intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.
AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.
<u><em>To Prove</em></u>: <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>
<em> </em><em><u>equal. </u></em>
<em><u>Solution</u></em>: Now, In ΔADM and ΔADN
∠MAD=∠NAD ...(1) (∵Given)
AD=AD ...(2) (∵common side)
∠ADM=∠ADN ...(3) (∵Given)
<u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>
( ∵ ASA congruence rule)
⇒<u><em> AM=AN</em></u>
Now, In Δ AMN
AM=AN (∵ Proved)
Hence, ΔAMN is an isosceles triangle.
