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Daniel [21]
3 years ago
5

In a certain school,260 students were present on monday,270 on tuesday,280 on wednesday,and 250 on thursday find the average num

ber of students present on those four days
Mathematics
1 answer:
Lunna [17]3 years ago
6 0

Answer:

The average number of students present are 265

Step-by-step explanation:

Given the number of students present on monday were 260, the number of students present on tuesday were 270 , the number of students present on wednesday were 280 , the number of students present on thursday are 250.

Now the numbers are 260, 270, 280, 250

We should basically find the average of these four observations

We know that the Average=\frac{sum of the observations}{number of observations}

sum of the observations is 260+270+280+250=1060

number of observations are 4

Average=  \frac{1060}{4}   =265

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Which of the following expressions is this one equivalent to?
schepotkina [342]

Answer: C. x-2

Step-by-step explanation:

We have the following expression:

\frac{x^{4} -2x^{3} +x-2}{x^{3}+1}

Factoring in the numerator:

\frac{x(x^{3}+1)-2(x^{3}+1)}{x^{3}+1}

Factoring again in the numerator with common factor x^{3}+1:

\frac{(x^{3}+1)(x-2)}{x^{3}+1}

Simplifying:

x-2

Hence, the correct option is C. x-2

3 0
3 years ago
Seven less than four times a number is 29 equation pleasee
Daniel [21]

4n - 7 = 29

That's the equation  :)

You can use any variable; doesn't have to be n.

If you want to solve for the variable, then it would be 5.5

6 0
2 years ago
Read 2 more answers
Amie has 9 cats. each cat eats 1/3 can of food each day. how many cans of food are used each day?
Basile [38]

Answer:

3 Cans.

Step-by-step explanation:

Each cat can take one portion. so

9 ÷ 3 = 3

3  cans a day

3 0
3 years ago
Eunice bought 585 beads.Jennifer bought 6 times more than Eunice but half of the total of beads Suin bought.How many beads did J
diamong [38]

Answer:

<em>Eunice 3510; Suin 7020</em>

Step-by-step explanation:

<em>Eunice bought 585 beads.</em>

<em>Jennifer bought 6 times more than Eunice</em> but half of the total of beads Suin bought.

Eunice: 6 * 585 = 3510

Jennifer bought 6 times more than Eunice but <em>half of the total of beads Suin bought.</em>

<em>Suin: 3510 * 2 = 7020</em>

7 0
3 years ago
The number of people arriving for treatment at an emergency room can be modeled by aPoisson process with a rate parameter of 5/h
saveliy_v [14]

Answer:

(a) The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is 3.75 arrivals.

Step-by-step explanation:

(a) If the arrivals can be modeled by a Poisson process, with λ = 5/hr, the probability of having exactly four arrivals during a particular hour is:

P(X=4)=\frac{\lambda^{X}*e^{-\lambda}  }{X!} =\frac{5^{4}*e^{-5}  }{4!}=\frac{625*0.006737947}{24} =\frac{4.211}{24}=0.1754

The probability of having exactly four arrivals during a particular hour is 0.1754.

(b) The probability that at least 3 people arriving during a particular hour can be written as

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))

Using

P(X)=\frac{\lambda^{X}*e^{-\lambda}  }{X!}

We get

P(X>3)=1-P(X\leq3)=1- (P(0)+P(1)+P(2)+P(3))\\P(X>3)=1-(0.0067+ 0.0337+ 0.0842 + 0.1404 )\\P(X>3)=1-0.2650=0.7350\\

The probability that at least 3 people arriving during a particular hour is 0.7350.

(c) The expected arrivals in a 45 minute period (0.75 hours) is

EV=\lambda*t=5*0.75=3.75

8 0
3 years ago
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