A bag contains tiles with the letters a-r-i-t-h-m-e-t-i-c. amelia chooses a tile without looking and doesn't replace it. she cho
oses a second tile without looking. what is the probability that she will choose the letter t both times
1 answer:
Sample space={A,R,I,T,H,M,E,T,I,C}
1ST (Choosing T) ==> P(1st draw) = 2/10 = 1/5 = 0.2
2ND (Choosing again a T) ==> P(2nd draw) = 1/9 = 0.11
Since it's a conditional probability then P (1st T AND 2nd T) = 0.2 x 0.11 =0.022
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