Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
x ≈ 31.0°
Step-by-step explanation:
From the right triangle given in the picture,
By applying tangent rule,
tan(x) = 
tan(x) = 
x = 
x = 
x = 30.96
x ≈ 31.0°
Therefore, measure of angle x is 30.0°
Answer:
We can just work backwards to find the value of x.
If 3 * x = 23,
then x = 23 / 3
and 23 / 3 = 7.6 reoccurring.
Step-by-step explanation:
Hope this helps:)
100^2/3
=³√1000^2
=³√1000000
Cube root the answer
³√1000000
=100. As a result, B is the correct answer. Hope it help!
Well, it says to use a calculator to calculate them. So a calculator I would highly recommend is the Desmos graphing calculator.
