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4 years ago

ANY QUESTION WILL DO!

2 answers:

8 0

For the first one, you can use the following "table"
1st week: $500. 200
2nd week : 500 - 20 = $480. 200 + 15 = $215
3rd week : 480 - 20 = $460. 215 + 15 = $230
4th week: 460 - 20 = $440. 230 + 15 = $245
5th week: 440 - 20 = $420. 245 + 15 = $260
6th week: 420 - 20 = $400. 260 + 15 = $275
7th week: 400 - 20 = $380. 275 + 15 = $290
8th week: 380 - 20 = $360. 290 + 15 = $305
9th week: 360 - 20 = $340. 305 + 15 = $320
10th week: 340 - 20 = $320 320 + 15 = $335
Hope this helps!!!

Ostrovityanka [42]4 years ago

3 0

I'll have Martin as X and Melvin as Y.

So the equation for X is, 15(starting point) and +5 every set.

Here's a table
________________
The amount of sets|Lbs -------->This one's for Y
__________________ ________________
0 | 15 0 | 60
1 | 20 1 | 50
2 | 25 2 | 40
3 | 30 3 | 30
4 | 35

On the third set, tables help. I'll do the first question in the comments

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Select the three number bonds that represent factor pairs of the number 56. CLEAR CHECK Number bond: 1 times 56 = 56. Number bon

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Answer:

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

Step-by-step explanation:

We can define a factor pair as a set of two factors, which, when multiplied together, give a particular product.

For example -

5 and 6 are factors of 30 because 5×6 = 30

Now,

Given -

Number bond: 1 times 56 = 56. ...................(1)

Number bond: 4 times 14 = 56. ...................(2)

Number bond: 5 times 6 = 56. ...................(3)

Number bond: 7 times 8 = 56. ...................(4)

In equation (1)

1 times 56 = 1×56 = 56

⇒1 and 56 are the factor pairs of 56

Satisfies

In equation (2)

4 times 14 = 4×14 = 56

⇒4 and 14 are factor pairs of 56

Satisfies

In equation (3)

5 times 6 = 5×6 = 30 ≠ 56

⇒5 and 6 are not factor pairs of 56

Not Satisfies

In equation (4)

7 times 8 = 7×8 = 56

⇒7 and 8 are factor pairs of 56

Satisfies

∴ we get

The answer is -

Number bond: 1 times 56 = 56.

Number bond: 4 times 14 = 56.

Number bond: 7 times 8 = 56.

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3 years ago

Solve the equation 2x^2+8x-1=0 by completing the square. Give your answer to 2 decimal places 4 marks

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Answer:

Step-by-step explanation:

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4 years ago

The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s

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Answer:

21 cm

Step-by-step explanation:

Call the triangle ABC, with the right angle at B, the hypotenuse AC=25, and the given leg AB=10. The altitude to the hypotenuse can be BD. Since the "other leg" is BC, we believe the question is asking for the length of DC.

The right triangles formed by the altitude are all similar to the original. That means ...

AD/AB = AB/AC . . . . . . ratio of short side to hypotenuse is a constant

Multiplying by AB and substituting the given numbers, we get ...

AD = AB²/AC = 10²/25

AD = 4

Then the segment DC is ...

DC = AC -AD = 25 -4

DC = 21 . . . . . centimeters

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I think it’s 3x

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