Answer:
The nth term is 109-9n
Step-by-step explanation:
Here, we want to find the nth term of the given arithmetic sequence
Mathematically, we have the nth term as;
Tn = a + (n-1)d
where a is the first term which is 100 in this case
d is the common difference which is the value obtained by subtracting the preceding term from the succeeding term; it is constant throughout the sequence
The value here is thus;
82-91 = 91-100 = -9
Substituting these values
Tn = 100 + (n-1)-9
Tn = 100 -9n + 9
Tn = 100 + 9 - 9n
Tn = 109-9n
You're looking for a value

such that

Because the distribution is symmetric, the value of

in either case will be the same.
Now, because the distribution is continuous, you have that

The mean for the standard normal distribution is

, and because the distribution is symmetric about its mean, it follows that

.

You can consult a

score table to find the corresponding score for this probability. It turns out to be

.
Answer:
55.734 mph
Step-by-step explanation:
Let's call the wind speed x and the time of flight t.
Then, we can write the following equation, knowing that the distance is equal speed times time of flight:
910 = (350+x) * t
660 = (350-x) * t
If we isolate t in both equations and compare its value, we have that:
910 / (350+x) = 660 / (350-x)
(350+x)/(350-x) = 910/660
350 + x = 1.3788 * (350-x)
350 + x = 482.58 - 1.3788x
2.3788x = 132.58
x = 55.734 mph
The square root of 400 is 20