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2 years ago

3x+2y= -19 solve by elimination of addition -3x-5y= 25

Mathematics

2 answers:

tensa zangetsu [6.8K]2 years ago

8 0

Answer:

x=-5, y=-2

Step-by-step explanation:

3x+2y= -19

-3x-5y= 25

Add the two equations together

3x+2y= -19

-3x-5y= 25

------------------

0x -3y = 6

Divide each side by -3

-3y/-3 = 6/-3

y = -2

Now find x

3x+2y = -19

3x +2(-2) =-19

3x-4 = -19

Add 4 to each side

3x -4+4 = -19+4

3x= -15

divide by 3

3x/3 = -15/3

x = -5

solong [7]2 years ago

5 0

Answer:

x = -5, y = -2

Step-by-step explanation:

3x + 2y = -19

-3x - 5y = 25

Add both equation together.

3x + 2y = -19
+ -3x - 5y = 25
0 x -3y = 6
-3y = 6

Divide each side by -3.

-3y/-3 = 6/-3
y = -2

Now, find x.

Substitute the value of y into the equation 3x + 2y = -19

3x + 2( -2 ) = -19
3x - 4 = - 19

Move the constant to the right hand side and change their sign.

3x = -19 + 4
3x = -15

Divide both side by 3.

3x / 3 = -15 / 3
x = -5

Therefore, x = -5 and y = -2

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Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

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Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

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2 years ago

What is the location of the point on the number line that is 3/5 of the way from a=2 to b=17

makkiz [27]

Answer:

Step-by-step explanation:

The distance that a is to b is b-a=17-2=15.

The line segment from a=2 to b=17 has length 15.

We need to know what is 3/5 of 15.

3/5 of 15 means what is 3/5 times 15?

(3/5)(15)=3(3)=9

So this means we are looking to make a line segment that is 9 units from 2 which is 2 to 11.

So 11 is 3/5 the way from a=2 to b=17.

Let's check from 2 to 11 that is a length of 9 and from 2 to 17 that is a length of 15.

Is 9/15 equal to 3/5?

Yes, 9/15 can be reduced to 3/5.

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