Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.
The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!
Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.
y>x-2 -6> -4-2 -6= -6
That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.
y>2x+2
-6>(2)(-4) +2
-6> -8 +2
-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.
If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.
Answer:
<h2>
y = ²/₅
x - 3</h2>
Step-by-step explanation:
Changing to slope-intercept form:
5x + 2y = 12 {subtract 5x from both sides}
2y = -5x + 12 {divide both sides by 2}
y = -⁵/₂
x + 6
y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1
{Two lines are perpendicular if the product of theirs slopes is equal -1}
y =-⁵/₂
x + 1 ⇒ m₁ = -⁵/₂
-⁵/₂×
m₂ = -1 ⇒ m₂ = ²/₅
So, any line perpendicular to 5x + 2y = 12 must have slope m =²/₅
100 = x + x/2
3x/2 = 100
x = 200/3
if there was 50% discount:
buying 1 would be $33.33
buying 2 would be $66.67
Y - x = 154
let z = xy = x(154 + x) = x^2 + 154x
we need to find the minimum value of z
z' = 2x + 154 which = zero for minm or maxm value
x = -77 and y = 154 -77 = 77
so the 2 numbers are -77 and 77
