Answer:
<em>700$.</em>
Step-by-step explanation:
20 ÷ 100 = <em>0.2</em>
0.2 x $3,500 = <em>700$</em>
Treat the matrices on the right side of each equation like you would a constant.
Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.
Then you can eliminate <em>Y</em> by taking the sum
4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>
==> <em>X</em> = (4<em>A</em> + <em>B</em>)/11
Similarly, you can eliminate <em>X</em> by using
-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>
==> <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11
It follows that

Similarly, you would find

You can solve the second system in the same fashion. You would end up with

12/30 is simplified to 2/5 and<span>number of students trying out the same for both boys and girls</span> 16/40 is also simplified to 2/5 so YES the number of students trying out is the same for both boys and girls. I hope this helps :)
Answer:
For the first 2 pages, you will want to count how many sides and angles for the stated figure above. Then you want to figure out what other figures that are related to the figure stated above. i.e. a square is a rectangle but not all rectangles are squares. On the last page you want to figure out what is the figure's name and other names that are related/same on the figure's original name. And lastly for part II you want to do the same thing for page 1 and 2, but instead you want to compare and contrast the 2 figures stated above. i.e. Parallelograms and Trapezoids.
Step-by-step explanation:
Hope this helps! :)
All you do is change signs write 2x minus 14 equals negative 10-14 equals four then you write 2x over two equals four over two then u write x equals negative two