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rodikova [14]
3 years ago
7

I need an equation example with an unknown factor?

Mathematics
2 answers:
anastassius [24]3 years ago
3 0
Lets say, I bought 3 cakes in the store and I spent $300, how much does a cake cost?
The equation representing that situation is the following, calling x the cake cost, our unknown factor:
3x = 300
we can solve this equation by dividing all equation by 3:
x = 100
therefore each cake costs $100
tia_tia [17]3 years ago
3 0
I want to buy eight bracelets, I don't know how much each bracelet costs, but the final cost will be $39.67.
The equation would look like this:
8 x <em>c</em> = 39.67
Where <em>c</em> equals cost.
To find the answer I would do the following:
8 x <em>c </em>= 39.67
<em>c</em> = 39.67 / 8
<em>c</em> ≈ 4.95
Each bracelet costs about $4.95.
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How much would you have to repay on a credit card debt of $3500 after three years if the interest
levacccp [35]

Answer:

<em>700$.</em>

Step-by-step explanation:

20 ÷ 100 = <em>0.2</em>

0.2 x $3,500 = <em>700$</em>

3 0
2 years ago
Please solve the problem ​
jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==>   <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==>   <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}

Similarly, you would find

Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}

You can solve the second system in the same fashion. You would end up with

P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}

3 0
3 years ago
Of th 30 girls who tried out for the lacrosse team team at Euclid middle school , 12 were selected. Of the 40 boys show tried ou
Harman [31]
12/30 is simplified to 2/5 and<span>number of students trying out the same for both boys and girls</span> 16/40 is also simplified to 2/5 so YES the number of students trying out is the same for both boys and girls. I hope this helps :)
3 0
3 years ago
PLZ PLZ WITH EXPLANATION
Vadim26 [7]

Answer:

For the first 2 pages, you will want to count how many sides and angles for the stated figure above. Then you want to figure out what other figures that are related to the figure stated above. i.e. a square is a rectangle but not all rectangles are squares. On the last page you want to figure out what is the figure's name and other names that are related/same on the figure's original name. And lastly for part II you want to do the same thing for page 1 and 2, but instead you want to compare and contrast the 2 figures stated above. i.e. Parallelograms and Trapezoids.

Step-by-step explanation:

Hope this helps! :)

8 0
2 years ago
Negative ten is no less than two times a number plus fourteen
creativ13 [48]
All you do is change signs write 2x minus 14 equals negative 10-14 equals four then you write 2x over two equals four over two then u write x equals negative two
5 0
3 years ago
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