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3 years ago

It’s possible to build a triangle with side lengths of 5,5, and 10

2 answers:

7 0

No. The two lengths 5 and 5 add up to 10; you'd have two sides of length 5 each placed end to end, equaling 10. That'd be represented by segments on a straight line, not a triangle.

Hope you've drawn a picture, so as to understand this better. ;)

OLga [1]3 years ago

4 0

No, as two sides (5 and 5) added together would equal 10. A triangle made with sides like that would just turn into a straight line.

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Basile [38]

3. adjacent, x=49
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3 years ago

Write an expression for the # of feet in x inches

disa [49]

There are 12 inches in a foot, so there should be 1/12 feet in an inch.
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4 years ago

1,000 + what gives us 1,200

Effectus [21]

Answer:

200 you know this lol

Step-by-step explanation:

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3 years ago

For a loan of $40,000 at 12% for 10 years, how much do you wind up paying back?

jek_recluse [69]

Answer:

$88,000

Step-by-step explanation:

40,000*.12= 4,800

4,800*10= 48,000

40,000+48,000= 88,000

8 0

3 years ago

1. How many ways are there to make an octagon with 19 different sticks when order DOESN’T matter?

Oksanka [162]

Answer:

1. 75582

2. 3047466240

Step-by-step explanation:

1. If order does not matter, this is a combination problem. You are choosing 8 sticks from a set of 19. (Octagons have 8 sides.)

The formula for combinations of n things chosen r at a time "n choose r" is

$_nC_r = \frac{n!}{r!(n-r)!}$

$_19C_8=\frac{19!}{8!(19-8)!} = \frac{19!}{8!11!}=75582$

2. If order matters, there are more possibilities. This is a permutation problem. The number of permutations of 19 things taken 8 at a time, "19 permute 8" is

$_nP_r=\frac{n!}{(n-r)!} \\ _{19}P_8=\frac{19!}{(19-8)!} = 3047466240$

6 0

3 years ago