For this case, the first thing we must do is define variables.
We have then:
x: number of times Giselle uses the athletic club
b: amount of money remaining
We write a linear equation of the form:
b = mx + c
Where,
m: slope of the line that represents the cost for each time she uses the athletic club
c: initial amount that Giselle paid
Substituting values we have:
b = -10x + 190
Answer:
a linear function that model the situation is:
d. b = 190 - 10x
You need to multiply three on both sides, add 6x to both sides, then divide by 4 on both sides. In the end, you will get y=3/2x+21/2.
Answer:
Elga is 32 years old.
Step-by-step explanation:
Let Alvin's age = A
Let Elga's age = E
Alvin is 10 years younger than Elga, so A = E - 10
The sum of their ages is 54, so A + E = 54
Replace the A in the second equation with E - 10, then solve for E.
A + E = 54 becomes (E - 10) + E = 54
Combine like terms
2E - 10 = 54
Add 10 to both sides
2E = 64
Divide both sides by 2
E = 32
Answer: hello your question is poorly written attached below is the complete question
answer:
attached below
Step-by-step explanation:
using
m^2 - 2m + 10 = 0
m = 2± (√4 - 4(1)(10)) / (2(1)) = 1 ± 3i
Hence the complementary function ; Yc = e^x ( C1 cos3x + C2 sin3x )
attached below is the detailed solution
