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galina1969 [7]
2 years ago
12

How do u estimate 5004​

Mathematics
2 answers:
Kay [80]2 years ago
8 0

Answer:

Step-by-step explanation:

You would have know to how much accuracy you want to know.   Estimates are about ball parking a number into some other idea about an easy way to understand what a number represents.   5,000 might be a good estimation for a distance that you're going to walk,   if the exact distance is 5,004.  You get a pretty good idea of how far , time wise, energy required ect ect.. when you say  5,000   So estimation is really about making the numbers easier to use and understand.   Numbers are "abstract"   they only represent ideas.

Brrunno [24]2 years ago
3 0

Answer:

5004 \approx5000

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Enter the number of complex zeros for the polynomial function in the box.
Monica [59]

Answer:

The answer is 3.

Step-by-step explanation:

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6 0
3 years ago
What is 8x-4y=-12;-3,-1,1 solve for y
polet [3.4K]
8x - 4y = -12
4y = 8x + 12
y = 8/4 x + 12/4
y = 2x + 3

When x = -3,
y = 2(-3) + 3 = -6 + 3 = -3
When x = -1,
y = 2(-1) + 3 = -2 + 3 = 1
When x = 1,
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3 0
3 years ago
Sushilis now 4 times as old as Sunil. 5 years ago Sushilwas 7 times as old as Sunil was then. Find the present ages of each of t
Illusion [34]

Answer:

Sunil = 10 and Sushil= 40

Step-by-step explanation:

Present ages-

Sushil= 4x

Sunil= x

5 years ago-

Sushil = 4x - 5

Sunil = x - 5

4x - 5 = 7(x - 5) = 4x - 5 = 7x - 35

                        = -5 = 3x - 35

                        = 30 = 3x

                        = 10 = x

So substitute the xs for 10-

Present Sushil= 4 x 10 = 40

Present Sunil= 10

6 0
3 years ago
What is the percent decimal and fraction of 12 out of 15
melomori [17]
Percent: 80%

Fraction: 12/15

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5 0
3 years ago
Read 2 more answers
2 A boat costs $18,800 and decreases in value by 12% per year. How much will the boat be worth after 13 years?
11111nata11111 [884]

\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &18800\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ t=\textit{elapsed time}\dotfill &13\\ \end{cases} \\\\\\ A=18800(1-0.12)^{13}\implies A=18800(0.88)^{13}\implies A\approx 3568.0636019

6 0
3 years ago
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