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3 years ago

What is the ABO Identification System & The Rh Factor?

2 answers:

Nutka1998 [239]3 years ago

7 0

ABO identification system is the system of determining the blood type of the Human being by checking the presence of Antigens "A" & "B" on the surface of their RBCs. If A is present, then it is A Blood group, if B, then it is B blood group, if both, then AB and if neither then it is called as O blood group.

Rh Factor is the type by which we classify individuals into two groups - Rh +ve with Rh factor on their surface and Rh - ve, which lacks of it

Hope this helps!

Llana [10]3 years ago

3 0

The second major blood grouping system is the Rhesus (Rh) system. Like the ABO blood types, the Rh factor is an inherited blood protein, or antigen, on red blood cells.

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What is the difference between a closed system and open?

Bond [772]

Answer: A “system in exchange of matter with its environment, presenting import and export, building-up and breaking-down of its material components.”

Explanation:

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3 years ago

Grade 8 Science

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3 years ago

0.265g of an organic compound produced an evaporation 102cm³ of vapour at 373k and 775mmHg percentage composition of the constit

kumpel [21]

A. The molecular mass of the compound is 77.9 g/mol

B. The molecular formula of the compound is C₆H₆

<h3>Determination of the mole of the compound</h3>

We'll begin by calculating the number of mole of compound using the ideal gas equation as shown below:

Volume (V) = 102 cm³ = 102 / 1000 = 0.102 L

Temperature (T) = 373 K

Pressure (P) = 775 mmHg = 775 / 760 = 1.02 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

n = PV / RT

n = (1.02 × 0.102) / (0.0821 × 373)

n = 0.0034 mole

<h3>A. Determination of the molecular mass of the compound. </h3>

Mass = 0.265 g

Number of mole = 0.0034 mole

Molecular mass =?

Molecular mass = mass / mole

Molecular mass = 0.265 / 0.0034

Molecular mass of compound = 77.9 g/mol

<h3>B. Determination of the molecular formula of the compound. </h3>

We'll begin by calculating the empirical formula of the compound.

Carbon (C) = 92.24%

Hydrogen (H) = 7.76%

Empirical formula =?

Divide by their molar mass

C = 92.24 / 12 = 7.69

H = 7.76 / 1 = 7.76

Divide by the smallest

C = 7.69 / 7.69 = 1

H = 7.76 / 7.69 = 1

Thus the empirical formula of the compound is CH

Finally, we shall determine the molecular formula.

Molecular mass = 77.9 g/mol

Empirical formula = CH

Molecular formula =?

Molecular formula = empirical × n = molecular mass

[CH]n = 77.9

[12 + 1]n = 77.9

13n = 77.9

Divide both side by 13

n = 77.9 / 13

n = 6

Molecular formula = [CH]n

Molecular formula = [CH]₆

Molecular formula = C₆H₆

Complete Question:

0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the constituent elements are 92.24% C and 7.76% H. Find the molecular mass and molecular formula of the composition.

Learn more about ideal gas equation:

brainly.com/question/14364992

Learn more about molecular formular:

brainly.com/question/512891

5 0

2 years ago

I need help finding this out

pishuonlain [190]

Its either b or c, but i think its b

8 0

3 years ago

Plz help!!! This is timed!!!