Hello!
To start off, we must look at atomic masses. Atoms all have different weights, so we must first find hydrogen and oxygen's atomic masses.
Oxygen: 16.00 amu
Hydrogen: 1.01 amu
Now, moving on to the weight of water itself. Water has the formula of H20, with two hydrogen atoms and one oxygen. Therefore, <u>add up the amus to get the weight of one molecule of water.</u>
1.01 + 1.01 + 16.00 = 18.02 amu
Now, to see the ratio of each component. Since hydrogen weighs a total of 2.02 amu (1.01 + 1.01) in the entire atom, we can state that hydrogen makes up about 0.112 of the weight of water. Now apply that ratio to 16 g, and solve.
0.112x = 16
142.857143 = x
So therefore, about 143 grams of water are made when 16g of hydrogen reacts with excess oxygen.
Hope this helps!
Answer:
Explanation:
To slow down this reaction, we can use any of the methods listed below:
- Increase the size of the magnesium by using solid lumps of the metal. This will take a much faster time to react than powered and granulated magnesium.
- Reduce the concentration of the acid.
- Let the reaction take place at a much lower temperature than that given.
These conditions will slow down a chemical reaction.
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.
Answer is 1.42x10^24
Answer:
.52 M
Explanation:
moles ÷ liters = molarity
2.45 ÷ 4.75 = 0.5157894737
rounding it = .52
