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mina [271]
4 years ago
13

HELP ASAP! WILL MARK YOU BRAINLIEST AND GIVE YOU 20 POINTS!

Chemistry
2 answers:
mixas84 [53]4 years ago
6 0

Answer: It would be the boiling point.

Explanation:

Because it is not a liquid nor a gas, that would mark the last two out. I'll have to guess that it is the boiling point of water.

olga_2 [115]4 years ago
6 0

It would be the second one. This is because if the ice is starting to melt and A is 0 it is getting hotter and 100 degrees is the melting point of water.

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A nucleus of mass number 81 contains 46 neutrons. an atomic ion of this element has 36 electrons in it. write the symbol for thi
nasty-shy [4]

A nucleus of mass number 81 contains 46 neutrons

Mass number=number of protons+number of neutrons

81=number of protons+ 46

number of protons=81-46

number of protons=35

In an atom, number of electrons=number of protons=35

So, the element is ⁸¹Br₃₅ .

Atomic ion of Br, having 36 electrons in it will be:

                                                                                      ⁸¹Br⁻₃₆

The symbol for this atomic ion will be Br and charge on the ion will be -ve.



8 0
3 years ago
Which electrons are the valence electrons of the atom?
Veronika [31]

Valence electrons are the electrons in the outermost shell, or energy level, of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell. We can write the configuration of oxygen's valence electrons as 2s²2p⁴
6 0
3 years ago
Equation: CH4 + 202 CO2 + 2H20
jeka94

Answer:

2:1

1.2 × 10² g

Explanation:

Step 1: Write the balanced combustion equation

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.

Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂

We will use the previously established molar ratio.

15 mol O₂   1 mol CH₄/2 mol O₂ = 7.5 mol CH₄

Step 4: Calculate the mass corresponding to 7.5 moles of CH₄

The molar mass of CH₄ is 16.04 g/mol.

7.5 mol × 16.04 g/mol = 1.2 × 10² g

4 0
3 years ago
Determine the freezing point of a solution which contains 0.31 mol of sucrose in 175 g of water. kf = 1.86ï°c/m
barxatty [35]
Freezing point depression is a colligative property.

The formula that rules it is:

ΔT f = Kf * m

Where m is the molality of the solution => m = moles of solute / Kg of solvent

=> m = 0.31 mol / 0.175 kg = 1.771 m

And kf = 1.86 °C/m

=> ΔTf = 1.771 m * 1.86 °C / m = 3.3 °C

 => Freezing point of the solution = normal freezing point of water - 3.3 °C = 0 - 3.3°C = - 3.3°C.

Answer: -3.3 °C


8 0
4 years ago
If a substance is ionic, then it likely will
Zielflug [23.3K]
Conduct electricity
3 0
3 years ago
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