(4x3+2x+6)+(2x3-x2+2)
Final result :
6x3 - x2 + 2x + 8
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 2 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((4•(x3))+2x)+6)+((2x3-x2)+2)
Step 2 :
Equation at the end of step 2 :
((22x3 + 2x) + 6) + (2x3 - x2 + 2)
Step 3 :
Checking for a perfect cube :
3.1 6x3-x2+2x+8 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 6x3-x2+2x+8
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 2x+8
Group 2: 6x3-x2
Pull out from each group separately :
Group 1: (x+4) • (2)
Group 2: (6x-1) • (x2)
Answer:
x + 6
Step-by-step explanation:
(f ÷ g)(x)
= 
factorise the numerator
= 
← cancel the factor (x + 3) on numerator/ denominator
= x + 6
Answer: 9-3x
Step-by-step explanation:
You add like terms
don't look at the 3x for now
positive 7 + positive 2 = 9
there is a negative sign next to 3x
9 goes first so
9 - 3x
Answer: Work done by both of them in k hours is
Explanation:
Since we have given that
Number of hours Mr. I does a job = x hours
Number of hours Mr. L does a job = y hours
Work done by Mr. I is given by
Work done by Mr. L is given by
Work done if they do together is given by
Work done if they work together for k hours is given by
Hence, work done by both of them in k hours is
If i am correct, these values should add to 360, so I do it by
140 + 110 + 62 = 312
360 - 312 = 48
So the value of the last side must equal 48.
Your answer would be x = -9. Proof:
If 9 is filled in, you would have
(3 - 5(-9))
(3 - (-45))
48
Then
48 + 140 + 110 + 62 = 360!
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