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2 years ago

What is the arc measure of ABC in degrees? B (20y – 11) (44 +6)/ P (7y - 7) \

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

5 0

Answer:

283 degrees

Step-by-step explanation:

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Work out the surface area of a sphere please help if u get it correct i’ll give h brainlest

Bingel [31]

Answer:

Surface area of sphere = 4πr²

r = radius

and radius = diameter/2

radius = 13/2

= 6.5cm

Surface area = 4 × π × 6.5

= 26 × π

= 81.68

= 81.7cm²

Hope this helps.

5 0

2 years ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

5 0

2 years ago

How to do this problem

zhuklara [117]

Answer:

What is the problem?

Step-by-step explanation:

Please upload.

3 0

2 years ago

What is the volume of this triangular Pyramid photo attached

storchak [24]

To find the volume of a triangular pyramid, the formula is:

$V=\frac{1}{3}(Area\text{ }of\text{ }thebase)(height)$

So we start by finding the area of the base, which is in the shape of a right triangle in this case.

The area of a right triangle is equal to 1/2 x base x height.

$\begin{gathered} A=\frac{1}{2}bh \\ \\ A=\frac{1}{2}(5)(6) \\ \\ A=15\text{ square feet} \end{gathered}$

We use this area to find the volume.

$\begin{gathered} V=\frac{1}{3}Ah \\ \\ V=\frac{1}{3}(15)(6) \\ \\ V=30\text{ cubic feet} \end{gathered}$

The volume of the triangular pyramid is 30 cubic feet.

3 0

1 year ago

How to factor expressions?<br> For example 4n + 4 • 2,<br> 10t + 10 • 3, 7v + 7 • 8

TiliK225 [7]

Answer:

8(n + 1)

30(t + 1)

56(v + 1)

Step-by-step explanation:

(4n + 4)(2)

4(n + 1)(2)

8(n + 1)

(10t + 10)(3)

10(t + 1)(3)

30(t + 1)

(7v + 7)(8)

7(v + 1)(8)

56(v + 1)

6 0

2 years ago