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3 years ago

Please help i’ll give brainless and show your work <3

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

8 0

{Q1:} Tyler walked 80% of Priya's distance.

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{Q2:} Priya walked 125% of Tyler's distance.

muminat3 years ago

7 0

<h3>Answer:</h3>

[1A] 8/10 × 100 = 80%

[1B] 10/8 × 100 = 125%

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Question 3 (Multiple Choice Worth 1 points)

Evgen [1.6K]

Answer:

$g(x) = x + 6$

Step-by-step explanation:

The parent function is given as:

$f(x) = x + 8$

We want to find a new function that results after shifting f(x), 2 units to the right.

Let that function be g(x), then

$g(x) = f(x - 2)$

We replace x by x-2 in f(x) to get:

$g(x) = x - 2 + 8$

When we simplify, we obtain:

$g(x) = x + 6$

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3 years ago

What's 187 divided by 7?

adell [148]

So,

187 divided by 7
187/7

Mixed: 26 5/7
Decimal: 26.714285 (there is a vinculum over the "714285")

3 0

3 years ago

Read 2 more answers

What does the "O" stand for in the S.T.O.P. method of refusal?

natima [27]

B.offer another idea hope i helped :)

3 0

3 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

5 0

3 years ago

J+3/8 if j Equals 3/8

hodyreva [135]

Answer:

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

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)

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Step-by-step explanation:Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

(

)

⋅

6 0

3 years ago