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zzz [600]
3 years ago
15

Sora was given two data sets, one without an outlier and one with an outlier. Data without an outlier: 108, 113, 105, 118, 124,

121, 109 Data with an outlier: 108, 113, 105, 118, 124, 121, 109, 61 How is the mean affected by an outlier? The outlier did not affect the mean at all. The outlier made the mean higher than all the other values. The outlier made the mean lower than all the other values. The mean is centered around all the other numbers in both sets of data.
Mathematics
2 answers:
gladu [14]3 years ago
8 0

The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...

The mean is centered among the other numbers in both sets of data.

_____

The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.

Nikitich [7]3 years ago
6 0

Answer:

The approved answer is wrong the answer was it was lower than all the others. I took the test

Step-by-step explanation:

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Simplify: -x + 8x if you can
adoni [48]

Answer:

7x

Step-by-step explanation:

-x + 8x =

8x - x =

7x

4 0
3 years ago
In a quiz its just middle school work so PLS help me
Tems11 [23]

Answer:

5.25x - 6

Step-by-step explanation:

<u>1.75x</u> -2 + <u>1.75x</u> -2 + <u>1.75x </u>-2

5.25x <u>- 2 - 2 - 2</u>

5.25x - 6

8 0
3 years ago
Read 2 more answers
Which statement is true?
Ipatiy [6.2K]

Given:

Circle with center P.

To find:

Which statement is true.

Solution:

In the circle P,

  • PT is a radius of the circle P.
  • VU is a diameter of the circle P.
  • SR is a secant of the circle P.
  • NQ is a tangent line and Q is a point of tangeny of circle P.

Option A:

N is a point of tangency on circle P.

It is is not true because Q is a point of tangency of circle P.

Option B:

PT is a secant of circle P.

It is not true because PT is a radius of the circle P.

Option C:

SR is a secant of circle P.

It is true by the above bulleted points.

Option D:

VU is a tangent of circle P.​

It is not true because VU is a diameter of the circle P.

Therefore SR is a secant of circle P is a true statement.

5 0
4 years ago
Read 2 more answers
A new surgical procedure is successful with probability of p. Assume that the operation is performed 5 times and the results are
DaniilM [7]

Answer:

a) P(X=5)=(5C5)(0.8)^5 (1-0.8)^{5-5}=0.32768

And we can use the following excel code: "=BINOM.DIST(5,5,0.8,FALSE)"

b) P(X=4)=(5C4)(0.6)^4 (1-0.6)^{5-4}=0.2592

And we can use the following excel code: "=BINOM.DIST(4,5,0.6,FALSE)"

c) P(X

And the excel code would be: "=BINOM.DIST(1,5,0.3,TRUE)"

d) E(X) =n*p= 5*0.5 =2.5

e) Var (X) = np(1-p) = 5*0.4*(1-0.4)=1.2

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=5, p)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case the value of p =0.8 and we want to find this probability:

P(X=5)=(5C5)(0.8)^5 (1-0.8)^{5-5}=0.32768

And we can use the following excel code: "=BINOM.DIST(5,5,0.8,FALSE)"

Part b

For this case the value of p =0.6 and we want this probability:

P(X=4)=(5C4)(0.6)^4 (1-0.6)^{5-4}=0.2592

And we can use the following excel code: "=BINOM.DIST(4,5,0.6,FALSE)"

Part c

The value of p assumed is 0.3. For this case we want this probability:

P(X

P(X=0)=(5C0)(0.3)^4 (1-0.3)^{5-0}=0.16807

P(X=1)=(5C1)(0.3)^4 (1-0.3)^{5-1}=0.36015

P(X

And the excel code would be: "=BINOM.DIST(1,5,0.3,TRUE)"

Part d

The expected value for the binomial distribution is given by np and since we are assuming p=0.5 we got:

E(X) =n*p= 5*0.5 =2.5

Part e

Assuming the value of p=0.4. The variance for the binomial distribution is given by:

Var (X) = np(1-p) = 5*0.4*(1-0.4)=1.2

7 0
3 years ago
jen has read ⁴/5 of a book. the next day she read ⅔ of what she had left . what fraction of the book is left to read?
Neporo4naja [7]
After Jen read 4/5 (12/15) of a book there was 1/5 left.
The next day she reads 2/3 of 1/5 which equals 2/15 of the book
So by 2 days 14/15 of the book is read and there is 1/15 left.


6 0
3 years ago
Read 2 more answers
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