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jenyasd209 [6]
4 years ago
14

In the F1 generation of a Mendelian cross,

Biology
2 answers:
Flura [38]4 years ago
7 0
In the F<span>1 </span>generation of a Mendelian cross,
only the dominant trait is visible.only the recessive trait is visible.neither the dominant nor recessive trait is visible.<span>both the dominant and recessive traits are visible.

-I believe the correct answer is "ONLY THE DOMINANT TRAIT IS VISIBLE" in F1 generation, it is when the two true breeds, both homo (same genes) cross for example, HH and hh, since H will always be present in a punnet square, the answer is ONLY THE DOMINANT TRAIT IS VISIBLE. key word VISIBLE, the dominant trait is H</span>
Klio2033 [76]4 years ago
6 0

Answer:

Explanation:

Only the dominant trait is visible

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A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 7.8 cm from the axis of rotation. (a) Calcul
Novosadov [1.4K]

Given data:

● Angular velocity of the turntable ω = 33 rev/min

Therefore,

ω = 33 rev/min

ω = 33rev/min × 2π rad/rev × 1 min/60 sec = 3.45 rad/s

● The distance of the watermelon seed from the axis of rotation r = 7.8 cm = 0.078 m

● μs = the coefficient of static friction

Section a:

The seed is undergoes circular motion and it is been effected by centripetal acceleration.

ac = rω^2

ac = 0.078 × 3.45^2

ac = 0.9284 m/s^2

Therefore,

the centripetal acceleration of the seed is 9.274 m/s^2

Section b:

If the seed is observed not to slip at the course of the circular motion, then the supplied frictional force given by the seed and surface of turntable would at least be equivalent to the centripetal force working on the seed.

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------------

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