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Sever21 [200]
2 years ago
11

Nadia has a can of vegetable with a mass of 411 grams what is the mass in centigrams

Mathematics
1 answer:
earnstyle [38]2 years ago
3 0
The can of vegetables is 41100 centigrams
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Solve (MAFS.912.A-REI.2.3)
Vikki [24]

Answer:

c,=2d=-2

Step-by-step explanation:

4 0
2 years ago
A (0, 2) and B (6,6) are points on the straight line ABCD.
elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points (x_1,y_1) and (x_2,y_2), the distance is denoted by: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Let's find the distance between A and B:

d = \sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = \sqrt{(6-a)^2+(6-b)^2}

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0
3 years ago
Read 2 more answers
How does tripling the side lengths of a right triangle affect its area?)
kap26 [50]
The area of the triangle will then be 9 times as great. 

The formula of the area of a triangle is 1/2bh, so if the base has been tripled and the height has been tripled, you're essentially multiplying 3 to the original equation twice (3 x 3 = 9).
6 0
3 years ago
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A rhombus has sides 11cm long the shorter diagonal of the rhombus is 8cm long find the size of the smaller angles of the rhombus
ZanzabumX [31]

Answer:

42.64°

Step-by-step explanation:

Note: A rhombus has all its sides equal, its opposite angle are equal, its  has bigger and smaller diagonal, diagonal bisect the angles and diagonal bisect each other.

From the diagram attached,

sinθ = opposite/adjacent

sinθ  = 4/11

θ = sin⁻¹(4/11)

θ = 21.32

Therefore, from the diagram,

The smaller angle of the rhombus = 2θ

The smaller angle of the rhombus = (2×21.32)

The smaller angle of the rhombus = 42.64°

8 0
3 years ago
Ydhdhdgshshsysyhsjdudhdndhdhdbdhdydbwjhswnjshdd​
SVETLANKA909090 [29]

Answer:

ty to the points :>

Step-by-step explanation:

tytytytysm

6 0
2 years ago
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