3 years ago

Please explain how to do this

Mathematics

1 answer:

Helen [10]3 years ago

8 0

9514 1404 393

Answer:

1/2

Step-by-step explanation:

The rules of exponents are helpful.

(a^b)^c = a^(bc)

a^-b = 1/a^b

$25^{\frac{1}{2}}\times10^{-1}=\dfrac{(5^2)^{\frac{1}{2}}}{10^1}=\dfrac{5^{2\cdot\frac{1}{2}}}{10}\\\\=\dfrac{5^1}{10}=\dfrac{5}{10}=\boxed{\dfrac{1}{2}}$

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Vadim26 [7]

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2 years ago

Read 2 more answers

Select the two binomials that are factors of this trinomial x^20 - x - 20

Mashcka [7]

Answer:

$(x-5)(x+4)$

Step-by-step explanation:

To factor the equation, break it into two binomials which multiply to make the equation. To write these binomials (x+a)(x+b), find factors which multiply to -20 and add to -1 for a and b.

20: 1, 2, 4, 5, 10, 20

-5+4 = -1

$x^2-x-20 = (x-5)(x+4)$