Question

Please explain how to do this

Answer 1

9514 1404 393

Answer:

  1/2

Step-by-step explanation:

The rules of exponents are helpful.

  (a^b)^c = a^(bc)

  a^-b = 1/a^b

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  $25^{\frac{1}{2}}\times10^{-1}=\dfrac{(5^2)^{\frac{1}{2}}}{10^1}=\dfrac{5^{2\cdot\frac{1}{2}}}{10}\\\\=\dfrac{5^1}{10}=\dfrac{5}{10}=\boxed{\dfrac{1}{2}}$