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vodka [1.7K]
3 years ago
10

On a particular day, the wind added 2 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 2 miles pe

r hour from her rate on her return trip. Jaime found that in the same amount of time she could row 42 miles with the wind, she could go only 34 miles against the wind. What is her normal rowing speed with no wind
Mathematics
1 answer:
masya89 [10]3 years ago
7 0

Take 42-2 = 40 and 34+2 = 36 so Jaime's normal rowing speed was 36 miles


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A.45<br> B.30<br> C.90<br> D.180<br> E.40<br> F.55<br> G.130<br> H.50
brilliants [131]

Answer:

m<4=40

Step-by-step explanation:

Supplementary angles form 180 degrees

m<3 is vertical to the 50 degree angle which is equal.

so. m<3=50

m<5=90

90+50=140

180-140=40

m<4=40

4 0
3 years ago
A group of 8 friends went to lunch and spent a total of $76, which included the food bill and a tip of $16. They decided to spli
storchak [24]

Answer:

Each Person:

-In tips: $2

-Food Bill: $7.50

Step-by-step explanation:

Let's find the tip amount for each person. $16 for the whole group. Each person will give in $2 for the tips, for a total of $16 in tips.

Now that tips are done, we must subtract the amount of tips from the food bill, to see how much each person pays. $76 - $16 = $60.

Divide 60 by 8 to get.. 60/8= 7.5.

With 7.5 as an answer, we can conclude that each person paid $7.50 for the food bill.

I see you need to select solutions, may I see them to help you out? The description is pretty vague..

5 0
2 years ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
What is the inverse of f(x)=(3x+2)/(5x-2)?
yKpoI14uk [10]

Answer:

y= 2x=2/5x - 3

Step-by-step explanation:

swap the variables: y=3x+25x−2 becomes x=3y+25y−2.

Now, solve the equation x=3y+25y−2 for y.

8 0
3 years ago
I need help on this question ASAP tysm
Ray Of Light [21]
I am stuck on one do those as well, try Socratic
5 0
3 years ago
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