2 QUESTIONS FOR DOUBLE POINTS!! 20 POINTS!!

Kevin is taking a taxi from the airport to his home. There is a $6 flat fee for riding in the taxi. In addition, Kevin must also

Andrej [43]

Answer:

1 times 6 everytimes you make a mile

Step-by-step explanation:

7 0

3 years ago

Which of the following illustrates the truth value of the given statements? January is the first month of the year or December i

Dafna11 [192]

First, the need to determine if the statements are true or false.

1) January is the first month of the year. (This statement is true)
2) December is the last month of the year. (This statement is also true)

With this in mind we can determine that what will illustrate the truth value would be:

T T -> T

In other words, since the first statement is true and the second statement is also true then conjunction of both statements would be true.

5 0

3 years ago

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Solve for x 4(−7x−2)−10=-3 + 5x+1

Hatshy [7]

Answer:

i think the answer is -33

Step-by-step explanation:

8 0

3 years ago

Tom Harris, a young father, is twenty-four years old. He wishes to purchase $7,000 of a ten-year term insurance. What will be hi

svetoff [14.1K]

<span>It would just be 4.15 times 7 which is </span>29.05

5 0

3 years ago

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Daily-high temperature measurements for 40 consecutive days are recorded for a particular city. The mean daily-high temperature

Vesnalui [34]

Answer:

$t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108$

$p_v =P(t_{39}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation

$\bar X=21.5$ represent the mean for the temperatures

$s=1.5$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =22$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:

Null hypothesis: $\mu \geq 22$

Alternative hypothesis: $\mu < 22$

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108$

P-value

We can calculate the degrees of freedom like this:

$df=n-1=40-1=39$

Since is a one left tailed test the p value would be:

$p_v =P(t_{39}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

5 0

3 years ago