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Vladimir [108]
3 years ago
12

In a trapezoid ABCD with legs AB and CD , the diagonals intersect each other at point O.

Mathematics
1 answer:
blondinia [14]3 years ago
3 0
Where are the choices??
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If you were to roll the dice one time what is the probability it will land on a 3? 
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Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)
vfiekz [6]

Answer:

Step-by-step explanation:

given a point (x_0,y_0) the equation of a line with slope m that passes through the  given point is

y-y_0 = m(x-x_0) or equivalently

y = mx+(y_0-mx_0).

Recall that a line of the form y=mx+b, the y intercept is b and the x intercept is \frac{-b}{m}.

So, in our case, the y intercept is (y_0-mx_0) and the x  intercept is \frac{mx_0-y_0}{m}.

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph (x_0,\frac{1}{x_0}). Which means that y_0=\frac{1}{x_0}

The slope of the tangent line is given by the derivative of the function evaluated at x_0. Using the properties of derivatives, we get

y' = \frac{-1}{x^2}. So evaluated at x_0 we get m = \frac{-1}{x_0^2}

Replacing the values in our previous findings we get that the y intercept is

(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}

The x intercept is

\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0

The triangle in consideration has height \frac{2}{x_0} and base 2x_0. So the area is

\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2

So regardless of the point we take on the graph, the area of the triangle is always 2.

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3 years ago
2x2-3 evaluate each expression. Show your work
nirvana33 [79]

Answer:

1

Step-by-step explanation:

2x2 = 4

4-3=1

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5x (x - 4) = 0<br> Solve it in standard form
murzikaleks [220]

Answer:

x=0 or x=4

Step-by-step explanation:

5x(x−4)=0

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QUICK!! TEN POINTS!! BRAINLIEST FOR WHOEVER GETS IT RIGHT!!
lara [203]

Answer:

(-2, -4.5)

Step-by-step explanation:

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