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Bad White [126]
3 years ago
13

If 4b-1=b, then 24b= ?

Mathematics
1 answer:
klemol [59]3 years ago
3 0

Answer:

Step-by-step explanation:

4b-1=b

3b-1=0

3b=1

b=1/3

24b=

24(1/3)=

8

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Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
two variables are negatively associated​ if, whenever the value of one variable​ increases, the value of the other variable decr
Flura [38]

Answer:

The correct answer is: Negative correlation.

Step-by-step explanation:

The negative correlation determines the relationship between two variables, it says that there is an inverse relationship between two variables, whenever one of them is decreasing, the other one increases, and it's the same in reverse.

6 0
3 years ago
No links or trolls please. I need help with this math, it’s due soon. Thanks you. It’s a division sign by the way, it’s hard to
xxTIMURxx [149]

Answer:

n^2p

Step-by-step explanation:

Thats the answer

3 0
3 years ago
2x^3-x^2+x-2 factorize​
bekas [8.4K]

Answer:

(x-1)(2x^2+x+2)

Step-by-step explanation:

Factorize:

f(x)=2x^3-x^2+x-2

<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

4 0
2 years ago
Read 2 more answers
Consider the following three points.(-5,2), (0,6), (6,4)Step 3 of 3: Determine whether the three points are collinear or not col
Anni [7]

Step 1

Collinear points are a set of three or more points that exist on the same straight line. Collinear points may exist on different planes but not on different lines.

Step 2

Graph the points; (-5,2),(0,6),(6,4)

Step 3

Conclude based on step 2

Since the points are not a straight line, we can conclude that the 3 points are not collinear.

3 0
11 months ago
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