Given:
The equation is:
To find:
The error in the given equation and correct it.
Solution:
We have,
Taking left-hand side, we get
![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)
It is not equal to right-hand side 
. In the right hand side, there must be a negative sign instead of positive sign.
Therefore, 
.
I think the answer is C...
1/3 wins and 2/3 losses
given 2 and 5 = 2/6 = 1/3
1, 3, 4, and 6 = 4/6 = 2/3
Answer:
Fraction: 81/100
Decimal: 0.81
Percentage: 81%
Step-by-step explanation:
The question is complete but the diagram mentioned can be found in
brainly.com/question/12188410
First step is to find the area of the whole square and then the area of the part that was shaded.
From the diagram, there are 100 squares in the whole square. 81 of those squares are shaded.
Area of the whole square = 10 by 10
= 10×10 = 100unit²
Area of shaded region = (10 by 8) + 1
= 80+1 = 81unit²
shaded area expressed as a fraction = 81unit²/100unit²
= 81/100
Shaded area expressed as a decimal = 81/100
You take the number 81 and carry the point by two decimal place from the right
= 0.81
Shaded area expressed as a percent of the whole = (81/100) × 100
= (81×100)/100
= 81%
