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dexar [7]
3 years ago
13

Find the coordinates of point Q that lies along the directed line segment from R(-2, 4) to S(18, -6) and partitions the segment

in the ratio of 3:7.
Please help!!

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0
Check the picture below

thus then

\bf \qquad \textit{internal division of a line segment}\\\\
R(-2,4)\qquad S(18,-6)\qquad
ratio1=3\qquad ratio2=7\qquad 3:7\\ \quad \\ \quad \\
\cfrac{RQ}{QS}=\cfrac{ratio1}{ratio2}\implies \cfrac{R}{S}=\cfrac{3}{7}
\implies 7R=3S
\\\\\\
7(-2,4)=3(18,-6)

\bf {{ Q=\left(\cfrac{\textit{sum of "x" values}}{ratio1+ratio2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{ratio1+ratio2}\right)}}\\ \quad \\
\qquad thus\qquad \\ \quad \\
Q=\left(\cfrac{(7\cdot -2)+(3\cdot 18)}{3+7}\quad ,\quad \cfrac{(7\cdot 4)+(3\cdot -6)}{3+7}\right)

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