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2 years ago

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A

Mathematics

2 answers:

m_a_m_a [10]2 years ago

6 0

Answer:

Step-by-step explanation:

Given,

A = { a , b , c , d }

B = { p , q , r , s }

Let's find the difference of two set A and B :

A - B = { a , b , c , d } - { p , q , r , s }

The difference of two sets A and B is denoted by A - B and defined as the set of all the elements of A only which are not in B.

⇒A - B = { a , b , c , d }

Now, let's find the difference of two sets B and A

B - A = { p , q , r , s } - { a , b , c , d }

Similarly, The difference of two sets B and A is denoted by B - A and defined as the set of the all elements of set B only which are not in A.

⇒ B - A = { p , q , r , s }

Hope I helped!

Best regards!!

Free_Kalibri [48]2 years ago

4 0

Answer:

A-B= (a,b,c,d)-(p,q,r,s)

=( )

B-A =(p,q,r,s)-(a,b,c,d)

( )

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48.75

Step-by-step explanation:

The salesmen makes a commission of 3.25%. So to get the percent into a usable form for this take 3.25 and divided by 100. You get 0.0325.

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2 years ago

Among U.S. cities with a population of more than 250,000 the mean one-way commute time to work is 24.3 minutes. The longest one-

joja [24]

Answer:

a) 9.18% f the New York City commutes are for less than 29 minutes.

b) 26.39% are between 29 and 36 minutes.

c) 67.55% are between 29 and 44 minutes

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 38.7, \sigma = 7.3$

What percent of the New York City commutes are for less than 29 minutes?

This is the pvalue of Z when X = 29.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 38.7}{7.3}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918.

So 9.18% f the New York City commutes are for less than 29 minutes.

What percent are between 29 and 36 minutes?

This is the pvalue of Z when X = 36 subtracted by the pvalue of Z when X = 29.

X = 36

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{36 - 38.7}{7.3}$

$Z = -0.37$

$Z = -0.37$ has a pvalue of 0.3557.

X = 29

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 38.7}{7.3}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918.

So 0.3557 - 0.0918 = 0.2639 = 26.39% are between 29 and 36 minutes.

What percent are between 29 and 44 minutes?

This is the pvalue of Z when X = 44 subtracted by the pvalue of Z when X = 29.

X = 44

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{44 - 38.7}{7.3}$

$Z = 0.73$

$Z = -0.37$ has a pvalue of 0.7673.

X = 29

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 38.7}{7.3}$

$Z = -1.33$

$Z = -1.33$ has a pvalue of 0.0918.

So 0.7673 - 0.0918 = 0.6755 = 67.55% are between 29 and 44 minutes

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likoan [24]

Answer:

<h3>13 years</h3>

Step-by-step explanation:

Let the present age of Alicia be x

Let the present age of her brother be y

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Her brother's age = y - 3

If three years ago Alicia was twice as old as her brother Carlos, then;

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x = 2y - 3 ...1

In two years time;

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x+2 = y + 2 + (0.5(y+2))

x+2 = y+2 + 0.5y + 1

x+2 = 1.5y+3

x = 1.5y + 1 ...2

Equating 1 and 2;

2y - 3 = 1.5y + 1

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Step-by-step explanation:

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2 years ago

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A​

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A