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Dahasolnce [82]
2 years ago
9

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A​

Mathematics
2 answers:
m_a_m_a [10]2 years ago
6 0

Answer:

<h3>A - B = { a , b , c , d }</h3>

<h3>B - A = { p , q , r , s }</h3>

Step-by-step explanation:

Given,

A = { a , b , c , d }

B = { p , q , r , s }

Let's find the difference of two set A and B :

A - B = { a , b , c , d } - { p , q , r , s }

The difference of two sets A and B is denoted by A - B and defined as the set of all the elements of A only which are not in B.

⇒A - B = { a , b , c , d }

Now, let's find the difference of two sets B and A

B - A = { p , q , r , s } - { a , b , c , d }

Similarly, The difference of two sets B and A is denoted by B - A and defined as the set of the all elements of set B only which are not in A.

⇒ B - A = { p , q , r , s }

Hope I helped!

Best regards!!

Free_Kalibri [48]2 years ago
4 0

Answer:

A-B= (a,b,c,d)-(p,q,r,s)

=( )

B-A =(p,q,r,s)-(a,b,c,d)

( )

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51 is 33 1/3 of what number?
nevsk [136]

Answer:

\boxed{\frac{153}{100}\:\:Or\:\:1.53}

Step-by-step explanation:

Let the number be n.


Then,

33\frac{1}{3} \tmes n=51

This implies that;

\frac{100}{3} n=51


We multiply both sides by \frac{3}{100} to obtain;


\frac{3}{100} \times \frac{100}{3}n=\frac{3}{100} \times 51


\Rightarrow n=\frac{3}{100} \times 51


\Rightarrow n=\frac{153}{100}

Or

\Rightarrow n=1.53


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3 years ago
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Answer:

m = -3

Step-by-step explanation:

5m + 20 = 8 + 2m +3

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3m + 20 = 11

3m = -9

m = -3

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3 years ago
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irinina [24]

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2 years ago
Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

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