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3 years ago

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A

Mathematics

2 answers:

m_a_m_a [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Given,

A = { a , b , c , d }

B = { p , q , r , s }

Let's find the difference of two set A and B :

A - B = { a , b , c , d } - { p , q , r , s }

The difference of two sets A and B is denoted by A - B and defined as the set of all the elements of A only which are not in B.

⇒A - B = { a , b , c , d }

Now, let's find the difference of two sets B and A

B - A = { p , q , r , s } - { a , b , c , d }

Similarly, The difference of two sets B and A is denoted by B - A and defined as the set of the all elements of set B only which are not in A.

⇒ B - A = { p , q , r , s }

Hope I helped!

Best regards!!

Free_Kalibri [48]3 years ago

4 0

Answer:

A-B= (a,b,c,d)-(p,q,r,s)

=( )

B-A =(p,q,r,s)-(a,b,c,d)

( )

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Based on such information, we form the following system of linear equations:

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There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

$a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }$

$a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}$

$a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}$

$b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }$

$b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}$

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$c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}$

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A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A​

A={a,b,c,d} B={p,q,r,s} find the value of A-B and B-A