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hjlf
3 years ago
7

In 10 mins a heart can beat up to 700 times. At this rate, in how many mins will a heart beat 140 times? At what rate can a hear

t beat?
Mathematics
1 answer:
Virty [35]3 years ago
5 0
At 2 minutes, the heart would beat 140 times.
700/10=70
140/70=2
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Which choice is equivalent to the expression below?
Andre45 [30]

<u>Answer:</u>

C. 4\sqrt{7} -4x\sqrt{7} is correct

<u>Steps</u><u>:</u>

4\sqrt{7} -3\sqrt{7}x-x\sqrt{7} \\\\4\sqrt{7} -3\sqrt{7} x-\sqrt{7} x\\\\4\sqrt{7} +(-3\sqrt{7} x-\sqrt{7} x)\\\\4\sqrt{7} -4\sqrt{7} x

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What value of s in the equation S/6=18?<br>A.108<br>B.24<br>C.12<br>D.3​
Fiesta28 [93]

Answer:

108

Step-by-step explanation:

s=18x6

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The line CD passes through the points C (2, -1) and D (1, 1). Which of the
inn [45]

Answer:

<em>The equation of the straight line in point - slope form</em>

<em>y +1 = -2 ( x-2)</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are C( 2,-1) and D(1,1)

Slope of the line

     m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } = \frac{1-(-1)}{1-2} = \frac{2}{-1} = -2

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<u>Step(ii):-</u>

Equation of the straight line passing through the point ( 2,-1) and having slope

m =-2

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<u><em>Final answer:-</em></u>

<em>The equation of the straight line</em>

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3 years ago
What is the next term of the geometric sequence?<br> 2,6,18,
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4 years ago
A weight lifter does 9.8 J of work while lifting a weight straight upward through a distance of 0.12m. What was the force exerte
gulaghasi [49]

Answer:

The force exerted by the weight lifter is 81.7 N.

Step-by-step explanation:

We can find the force exerted by the weight lifter using the definition of work:

W = F*d    (1)

Where:

F: is the force

d: is the displacement

We have W = 9.8 J of work and d = 0.12 m, so by solving equation (1) for F we have:

F = \frac{W}{d} = \frac{9.8 J}{0.12 m} = 81.7 N

Therefore, the force exerted by the weight lifter is 81.7 N.

I hope it helps you!                          

3 0
3 years ago
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