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3 years ago

Round 155,016 to the nearest thousand

1 answer:

7 0

Round 155 016 to the nearest thousand.
Let us first identify the place value of each digits
=> 6 = ones
=> 1 = tens
=> 0 = hundreds
=> 5 = thousands
=> 5 = ten thousands
=> 1 = hundred thousands

Now, the situation is asking to round to the nearest thousand
=> 155 016 is equals to 155 000 when rounded to the nearest thousand
because the number next to thousands is 0, and 0 is below 5 so apply rounding down.

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What is the value of x?

Len [333]

Answer:

x=3

Step-by-step explanation:

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3 years ago

A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?

Leya [2.2K]

Ok, so you are given an equation in standard form, 5x+4y=2, and a point, (7, 5). You are being asked to write the equation for a line that is parallel to the equation in standard from, and that includes the point (7, 5).

First, let's start by finding the slope of your new line. We know that it needs to have the same slope as 5x+4y=2, because parallel lines have the same slopes. To do that, we need to put the equation into slope-intercept form (y=mx+b), which means we need to isolate the "y."

5x+4y=2

-5x -5x (subtract 5x from both sides to move it to the right side of your equation)

4y = 2 - 5x

/4 /4 /4 (divide all the terms by 4 to get "y" by itself)

y = (1/2) - (5/4)x ... I suggest leaving your slope as a fraction.

Now, we know that our slope, m , is going to be -(5/4).

Next, we are going to use our slope, -(5/4), and point, (7, 5), to find the b-value (y-intercept) of your new line. Let's plug in what we know:

y = 5

m = -(5/4)

x = 7

y=mx+b

5=(-5/4)(7) + b -> I plugged in what we knew for y, m, and x.

5 = -(35/4) + b -> I multiplied the numbers in the numerator (5 x 7) to get 35/4

20/4 = -(35/4) + b -> I converted 5 into a faction with a denominator of 4 by multiplying by (4/4)

+(35/4) +(35/4) -> I add (35/4) to both sides to isolate b

55/4 = b ... or b = 13.74

Answer:

m = -(5/4)

b = 13.75

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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Neporo4naja [7]

If they're integers, that means they can't be fractions (such as 15/2 and 2).

So the only couples of integers that, when multiplied, result in 15 are:

1 and 15
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(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.

The least possible sum of a and b is 8.

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