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2 years ago

Round 155,016 to the nearest thousand

1 answer:

7 0

<span>Round 155 016 to the nearest thousand.
Let us first identify the place value of each digits
=> 6 = ones
=> 1 = tens
=> 0 = hundreds
=> 5 = thousands
=> 5 = ten thousands
=> 1 = hundred thousands

Now, the situation is asking to round to the nearest thousand
=> 155 016 is equals to 155 000 when rounded to the nearest thousand
because the number next to thousands is 0, and 0 is below 5 so apply rounding down.</span>

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If you put it into a calculator, you get 35/8 as a fraction and you can change it to a decimal and get 4.375.

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3 years ago

Someone help me get my head around this ?<br> ((the fraction part))

PtichkaEL [24]

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Step-by-step explanation:

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2 years ago

The area of a rectangular pool is 8342 m .<br> If the width of the pool is 86 m, what is its length?

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Answer:

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Step-by-step explanation:

The area of a rectangle is its length multiplied by its width. Substitute the known values into this equation and solve for the length, l:

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2 years ago

Read 2 more answers

The SAT Reasoning Test (formerly called the Scholastic Aptitude Test) is perhaps the most widely used standardized test for coll

mihalych1998 [28]

Given Information:

Mean SAT score = μ = 1500

Standard deviation of SAT score = σ = 3 00

Required Information:

Minimum score in the top 10% of this test that qualifies for the scholarship = ?

Answer:

$\bar{x} = 1884\\$

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.

We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

$P(X > \bar{x} )= P(Z > \bar{x}) = 0.10\\P(X < \bar{x} )= P(Z < \bar{x}) = 1 - 0.10\\P(X < \bar{x} )= P(Z < \bar{x}) = 0.90\\$

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

$\bar{x} = \mu + z(\sigma) \\\bar{x} = 1500 + 1.28(300)\\\bar{x} = 1500 + 384\\\bar{x} = 1884\\$

Therefore, you need to score 1884 in order to qualify for the scholarship.

How to use z-table?

Step 1:

In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2

Step 2:

Then look up at the top of z-table and note down the value of the that column which is 0.08

Step 3:

Finally, note down the intersection of step 1 and step 2 which is 1.28

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2 years ago

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C
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