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polet [3.4K]
3 years ago
6

Rename numbers using a place value chart

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
6 0
ones tens hundreds thousands millions billions and those are all the place value chart
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Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]
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Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

f(x)=\dfrac{2x-1}{2}

We need to find the average value of the function on the given interval [1,13].

f(x)=\dfrac{2x}{2}-\dfrac{1}{2}

f(x)=x-0.5

The average value of the function f(x) on [a,b] is

Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx

Average value of the function on the given interval [1,13] is

Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx

Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}

Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]

Average=\dfrac{1}{12}[78-0]

Average=6.5

Therefore, the average value of the function on the given interval 6.5.

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3 years ago
600 s =how many minutes
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I need help with 31 please
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Answer and Step-by-step explanation:

I am not completely sure of how to put it together because I wasn't shown how you guys did this with previous problems, so I will do my best.

2x^2-3x-2 - (x^2 -1+3)

I think this is the answer, with each of the numbers representing how many of the squares/rectangles that are there.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u></u></em>

<em><u>I hope this helps!!</u></em>

<em><u></u></em>

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