Answer:
The average value of the function on the given interval 6.5.
Step-by-step explanation:
Consider the given function is

We need to find the average value of the function on the given interval [1,13].


The average value of the function f(x) on [a,b] is

Average value of the function on the given interval [1,13] is

![Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7Bx%5E2%7D%7B2%7D-0.5x%5D%5E%7B13%7D_%7B1%7D)
![Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B%5Cdfrac%7B%2813%29%5E2%7D%7B2%7D-0.5%2813%29-%28%5Cdfrac%7B%281%29%5E2%7D%7B2%7D-0.5%281%29%29%5D)
![Average=\dfrac{1}{12}[78-0]](https://tex.z-dn.net/?f=Average%3D%5Cdfrac%7B1%7D%7B12%7D%5B78-0%5D)

Therefore, the average value of the function on the given interval 6.5.
600/60=10
600 seconds equals 10 minutes
Based on this information... there should be about 630 skaters in 2006. I hope this helps.
Anthony can conclude that the difference is significant, because a two minutes difference is not likely to happen by chance. In analyzing data, a statistically significant result is one which is not attributed to chance, that is, there is no way the event could have occur by chance.
Answer and Step-by-step explanation:
I am not completely sure of how to put it together because I wasn't shown how you guys did this with previous problems, so I will do my best.

I think this is the answer, with each of the numbers representing how many of the squares/rectangles that are there.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
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<em><u>I hope this helps!!</u></em>
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