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beks73 [17]
3 years ago
8

2(5x + 7) = 34 Someone help me

Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

2(5x + 7) = 34

10x + 14 = 34

10x = 34 - 14

10x = 20

x = 20/10

x = 2

jonny [76]3 years ago
6 0

Answer:

2

Step-by-step explanation:

34 divided by 2 is 17

-7 is 10

divided by 5 which is 2

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A trout lurking 32 cm below the surface of a lake spies an insect flying 17cm above the lake. How many centimeters would the tro
Bumek [7]

Answer:

The Trout will have to jump 49 cm in order to catch the insect

Step-by-step explanation:

Here, we want to calculate the distance the Trout has to jump in order to catch the Insect

To calculate this, we need to know the difference in the distances

From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake

The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;

17 + 32 = 49 cm

3 0
2 years ago
Find the area of the court<br><br>​
Romashka [77]

Answer:

7.4.      I BELIEVE...sorry if i did it wrong

Step-by-step explanation:

1 2/3 + 1 2/3 = 3.33333333

2 + 2 = 4

3.333333 + 4 = 7.333333

7.333333 rounded would be 7.4

8 0
2 years ago
Simplify 3(2x + 5) <br> A. 6x + 30 <br> B.6x + 15<br> C. 6x + 5
Nana76 [90]

3(2x/5)  

Final result :

 6x

 ——

 5  

Step by step solution :

Step  1  :

           x

Simplify   —

           5

Equation at the end of step  1  :

          x

 3 • (2 • —)

          5

Step  2  :

Final result :

 6x

 ——

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5 0
3 years ago
Read 2 more answers
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Please help.in need to find the coordinates of L and I need to find her error
victus00 [196]

Answer:

See below

Step-by-step explanation:

She rotated clockwise but needs to go counterclockwise. It should be (-4, 2)

7 0
2 years ago
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