Step-by-step explanation:
we can begin by expressing the equation in
slope-intercept form









![plot \: (0,2) \: and \: (2,0) \: and \: draw \: a \: straight \: line \: through \: them \: graph \: ({-x+2 [-10, 10, -5, 5]}](https://tex.z-dn.net/?f=%3C%2Fp%3E%3Cp%3Eplot%20%20%5C%3A%20%280%2C2%29%20%20%5C%3A%20and%20%20%5C%3A%20%282%2C0%29%20%5C%3A%20%20and%20%5C%3A%20%20draw%20%20%5C%3A%20a%20%20%5C%3A%20straight%20%5C%3A%20%20line%20%20%5C%3A%20%3C%2Fp%3E%3Cp%3Ethrough%20%5C%3A%20%20them%20%5C%3A%20%3C%2Fp%3E%3Cp%3Egraph%20%5C%3A%20%28%7B-x%2B2%20%5B-10%2C%2010%2C%20-5%2C%205%5D%7D)
The scale factor is 0.25, not 4 in this case. You can determine this by looking at the comparison of the triangles. The first triangle is 4.4 and the second one is 1.1, so the scale factor is determined by looking at what is happening to the first one to result in the second.
0.25 is 1/4. The second hypotenuse is 1/4 the hypotenuse of the first one.
(0,-3) (2,1) is the two points we are going to use.
M=(1--3)/(2-0)=4/2=2
The slope is 2