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gizmo_the_mogwai [7]
3 years ago
6

Find the value of x. A 4 B 6 C 3 D 2

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer: x=4

Step-by-step explanation:

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Solve this by substitution
frozen [14]

Answer:

y= 1 and x=-2

Step-by-step explanation:

Since they both equal y, you can equal them to each other:

x + 3 = 2x + 5

Then solve:

x - x + 3 = 2x - x + 5

3 - 5 = x + 5 - 5

-2 = x

Substitute x in either equation to solve for y:

y = (-2) +3

y = 1

Or the other equation:

y = 2(-2) + 5

y = -4 + 5

y = 1

hope this helps :)

6 0
3 years ago
ABCDEF is a regular hexagon. AJFGH is a regular pentagon
Ede4ka [16]
Please finish the sentence(s). This doesn’t have enough information. Have a good day
3 0
3 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
A true-false question is to be posed to a husband and wife team. Both the husband and the wife will give the correct answer with
marysya [2.9K]

Answer:

Choose either strategy both are equally successful

Step-by-step explanation:

Given:-

- The probability of success for both husband (H) and wife (W) are:

                              P ( W ) = 0.8 , P ( H ) = 0.8

Find:-

- Which of the following is a better strategy for the couple?

Solution:-

Strategy 1

- First note that P ( W ) & P ( H ) are independent from one another, i.e the probability of giving correct answer of husband does not influences that of wife's.

- This strategy poses an event such that either wife knows the answer and answer it correctly or the husband knows and answers in correctly.

- We will assume that probability of either the husband or wife knowing the answer is 0.5 and the two events of knowing and answering correctly are independent. So,

                           P ( Wk ) = P (Hk) = 0.5

- The event P(S1) is:

                           P(S1) = P ( Hk & H ) + P ( Wk & W )

                           P(S1) = 0.5*0.8 + 0.5*0.8

                           P(S1) = 0.8

- Hence, the probability of success for strategy 1 is = 0.8

Strategy 2

- Both agree , then the common answer is selected otherwise, one of their answers is chosen at random.

- The success of strategy 2, will occur when both agree and are correct, wife is correct and answers while husband is not or husband is correct and he answers.

- The event P(S2) is:

                   P(S2) = P ( H & W ) + P ( H / W' & Hk ) + P ( H' / W & Wk )

                   P(S2) = P ( H & W ) + P ( H / W') P ( Hk ) + P ( H' / W) P (Wk)

                   P(S2) = P ( H & W ) + P ( H / W')*0.5  + P ( H' / W)*0.5

                   P(S2) = 0.5* [ P ( H & W ) + P ( H / W') ]  + 0.5* [ P ( H' / W) + P ( H & W )]

                   P(S2) = 0.5*P(H) + 0.5*P(W)

                   P(S2) = 0.5*0.8 + 0.5*0.8

                   P(S2) = 0.8

- Hence, the probability of success for strategy 2 is = 0.8

Both strategy give us the same probability of success.

                 

                       

4 0
3 years ago
Please help me please thank you
AleksandrR [38]

Answer:

x = 15

Step-by-step explanation:

angles 2 and 4 are supplementary so they add up to 180

2x + 10 + 4x + 80 = 180

6x + 90 = 180

6x = 90

x = 15

7 0
3 years ago
Read 2 more answers
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