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BaLLatris [955]
3 years ago
5

How do an independent variable and a dependent variable differ in a scientific investigation?

Chemistry
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

stop cheating and be smart

Explanation:

ugh sjdjdkxkdkdkdkdkdkdahahahajajaja

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An ice cube melts and then the liquid water evaporates. Which statement is true about the mass of water that goes through each c
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Answer:

it changes.

Explanation:

when in solid form it has an amount of mass. but when evaporated, water is pretty much massless.

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What type of wave can actually reach Earth's inner core
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I believe body waves can actually reach the core as they follow raypaths refracted by the varying density and modulus of Earths interior.

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3 years ago
What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the de
Dvinal [7]

Here is the full question

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm until the height of the alcohol column is 10 cm. The two liquids do not mix.

What is the difference in height between the top surface of the glycerin and the top surface of the alcohol? Suppose that the density of glycerin is 1260 kg/m3and the density of alcohol is 790 kg/m3.

Express your answer in two significant figures and include the appropriate units (in cm)

Answer:

ΔH ≅ 3.73 cm

Explanation:

The pressure inside a liquid is known as hydrostatic pressure and which is represent by the formula:

P =   ρ × g × h

where;

ρ is the density of the fluid

g is the gravitational constant

h is the height from the surface

From the question above;

For glycerine; we have:

density of glycerine = 1260 kg/m³

gravitational constant = 9.8 m/s²

height = ???

∴

P_{(g)= 1260kg/m^3}*9.8m/s^2*h_g   ----- equation (1)

On the other hand for alcohol:

density of alcohol is given as = 790 kg/m³

gravitational constant = 9.8 m/s²

height = 10 cm

∴

P_{(a)= 790kg/m^3*9.8m/s^2*10           ----------- equation (2)

if we equate equation 1 and 2 together; we have

P_{(g)= P_{(a)

1260kg/m^3}*9.8m/s^2*h_g = 790kg/m^3*9.8m/s^2*10cm

Making h_g the subject of the formula, we have :

h_g= \frac{ 790kg/m^3*9.8m/s^2*10cm}{1260kg/m^3*9.8m/s^2}

h_g = 6.269 cm

The difference in the height denoted  by ΔH can therefore be calculated as:

ΔH = H_a-H_g

ΔH = 10cm - 6.269cm

ΔH = 3.731 cm

ΔH ≅ 3.73 cm           (to two significant figures)

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The chemical formula for diiodine nonaflouride
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