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3 years ago

Solve this please: 2/5X + 1.5y = 7X - 2y 20 points!!!! Thank y'all!

Mathematics

1 answer:

UNO [17]3 years ago

4 0

2/5x + 1.5y = 7x - 2y
1.5 y + 2y = 7 x - 2/5x
You can this
1.5 y + 2y = 7x - 0.4x
3.5y = 6.6x

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5-2x=15 <img src="https://tex.z-dn.net/?f=5%20-%202x%20%3D%2015" id="TexFormula1" title="5 - 2x = 15" alt="5 - 2x = 15" align

padilas [110]

5-2x=15

 $5-2x=15 \\ \\ -2x= 15-5 \\ \\ -2x= 10 \\ \\ x= \dfrac{10}{-2} \to \boxed{x= -5}$

6 0

4 years ago

What is 16.2 simplified (and 121 simplified to)

Cerrena [4.2K]

Answer:

16.2 = $\frac{81}{5}$ and 121 = $\frac{121}{1}$

Step-by-step explanation:

16.2 can be simplified to its fraction form, which is $\frac{81}{5}$

$16+\frac{2}{10} =\frac{81}{5}$ which is 16.2

121 is already simplified since it is a whole number, but its fraction form would be $\frac{121}{1}$

$121+\frac{0}{10} =121$ which is 121

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(I hope this helped & good luck! <3)

7 0

3 years ago

(2/3x+2) - (1/3x - 4)

DiKsa [7]

Answer:

simplified: 6 + x/3

Step-by-step explanation:

(2/3x+2) - (1/3x - 4)

= 6 + x/3 .

Hope this helps !

6 0

3 years ago

If the area of a circle is 90 cm, what is its radius?

Mademuasel [1]

Answer:

r= 5.35

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Assume that the number of customers who arrive at a water ice stand follows the Poisson distribution with an average rate of 6.4

Nady [450]

Answer:

18.88% probability that three or four customers will arrive during the next 30 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Average rate of 6.4 per 30 minutes.

This means that $\mu = 6.4$

What is the probability that three or four customers will arrive during the next 30 minutes?

$P = P(X = 3) + P(X = 4)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-6.4}*(6.4)^{3}}{(3)!} = 0.0726$

$P(X = 4) = \frac{e^{-6.4}*(6.4)^{4}}{(4)!} = 0.1162$

$P = P(X = 3) + P(X = 4) = 0.0726 + 0.1162 = 0.1888$

18.88% probability that three or four customers will arrive during the next 30 minutes

4 0

4 years ago