This ODE is separable; we have
![\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dt%7D%3Dky%5Cimplies%5Cdfrac%7B%5Cmathrm%20dy%7Dy%3Dk%5C%2C%5Cmathrm%20dt)
Integrating both sides gives a general solution of
![\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}](https://tex.z-dn.net/?f=%5Cln%7Cy%7C%3Dkt%2BC%5Cimplies%20y%3De%5E%7Bkt%2BC%7D%3DCe%5E%7Bkt%7D)
B is the only choice that is applicable.
Answer:
That p is parallel to Q./??
Step-by-step explanation:
Answer:
11 minutes and 15 seconds
Step-by-step explanation:
Try a protractor to solve it
It would be c because a linear function can be in y-intercept form(y=mx+b) which y=x+3 is in.